The quadratic formula is expressed as:
x = (-b +/- √(b^2 - 4ac) ) / 2a
where a, b and c are the coefficients of the quadratic equation with the form ax^2 + bx + c=0
Therefore, the quadratic equation would be:
a = 3
b = -6
c = 8
x = (-(-6) +/- √((-6)^2 - 4(3)(8) ) / 2(3)
Hope this helps.
The answer is: -3r+15r
you will multiply -3*5 first then -3*-r
Answer:
1) Sometimes
2) Always
3) Never
4) Always
5) Sometimes
Step-by-step explanation:
1) Sometimes
2) Always
3) Never
4) Always
5) Sometimes
<h3><u>d^3 - 4bd^2 + 16b^2d - 64d^3 is the expanded binomial.</u></h3>
The binomial theorem involves Pascal's triangle, and essentially gives you the coefficients for the formula you're going to use to expand it.
In this case, the coefficients will be 1, 3, 3, and 1.
We can set up our formula like this:
(a + (-b)) = a^3 + a^2b + ab^2 + b^3
Now we can just plug in our values:
(d + (-4b))^3 = d^3 + d^2(-4b) + d(-4b)^2 + (-4b)^3
Now, we can simplify the equation.
(d + (-4b))^3 = d^3 - 4bd^2 + 16b^2d - 64d^3
