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Vlad [161]
3 years ago
12

Pamela earns $221 for 26 hours of work. How much does Pamera earn for 40 hours of work?

Mathematics
2 answers:
Mila [183]3 years ago
6 0
$340. I hope this helps
Ostrovityanka [42]3 years ago
3 0

Answer:

Step-by-step explanation:

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How many dimes and nickels make 6.10 dollars if there are 79 coins
7nadin3 [17]

Answer:

50 dimes and 29 nickels

Step-by-step explanation:

4 0
2 years ago
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PleaseeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeSimplify -2^3
mars1129 [50]

Answer:

Therefore,

(-2)^{3}=-8

Step-by-step explanation:

Simplify

-2^3

(-2)^{3}

It is read as negative 2 raised to the power three,

also it is the cube of negative 2

we know that a^{3}given as

a^{3}=a\times a\times a

so for negative a i.e -a

(-a)^{3}=-a\times -a\times -a

substituting a = 2 we get

(-2)^{3}=-2\times -2\times -2

negative sign multiplied by odd number of times then the sign remains negative.

Therefore,

(-2)^{3}=-8

5 0
3 years ago
(50 pts!) Help pls<br><br>Find the value of x
Lera25 [3.4K]

Answer:

x = 3.5.

Step-by-step explanation:

This is an equilateral triangle ( as all angles = 60 degrees) so all 3 sides are of equal length.

Thus 2x - 3 = 4

2x = 7

x = 3.5.

4 0
2 years ago
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Your uncle lives 20 miles away. So far, your family has driven 6 miles toward your uncle's house. How
patriot [66]
14 miles 20-6!!! Good luck
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3 years ago
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If $10,000 is invested at an annual rate of 11%, compounded quarterly, find the value of the investment after the given number o
lana [24]

Answer:

a) A\simeq17204.28

b) A\simeq29598.74

c)A\simeq50922.51

Step-by-step explanation:

The amount formula in compound interest is:

A=P(1+\frac{r}{n} )^{nt}

where:

P = principal amount

r = annual interest

n = number of compounding periods

t = number of years

We already know that:

P = $10000

r = 11\% = \frac{11\%}{100\%}=0.11

n = 4 (quarterly in a year)

a ) t = 5 years

A=10000(1+\frac{0.11}{4} )^{(4)(5)}\\\\A=10000(1+\frac{0.11}{4} )^{20}\\\\A=17204.28431\\\\A\simeq17204.28

b) t = 10 years

A=10000(1+\frac{0.11}{4} )^{(4)(10)}\\\\A=10000(1+\frac{0.11}{4} )^{40}\\\\A=29598.73987\\\\A\simeq29598.74

c) t = 15 years

A=10000(1+\frac{0.11}{4} )^{(4)(15)}\\\\A=10000(1+\frac{0.11}{4} )^{60}\\\\A=50922.51361\\\\A\simeq50922.51

5 0
2 years ago
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