Answer: -3 and 5
<u>Step-by-step explanation:</u>
Let x represent the 1st digit and y represent the 2nd digit. Then,
Eq 1: 2x + 3y = 9 → 3(2x + 3y = 9) → 6x + 9y = 27
Eq 2: 3x + 2y = 1 → -2(3x + 2y = 1) → <u>-6x - 4y = -2</u>
5y = 25
y = 5
Substitute y = 5 into either of the original equations to solve for x:
2x + 3y = 9
2x + 3(5) = 9
2x + 15 = 9
2x = -6
x = -3
Check (using the other original equation):
3x + 2y = 1
3(-3) + 2(5) = 1
-9 + 10 = 1
-1 = 1 
Hi - if you could provide a diagram, i could definitely help you!
Answer:
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f(7)≈1.6666 Please mark me as brainliest
round
f(7)=1.67
The domain of the function is the set of all the values of x that would allow the function to have real values. Since the radicand is x - 3, the value of x cannot be less than 3 because that would make the value of sqrt (x - 3) an imaginary number. Thus, the domain should be all numbers GREATER than or equal to 3.
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