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Elena L [17]
3 years ago
13

What is a factor of 98

Mathematics
1 answer:
ziro4ka [17]3 years ago
8 0

Answer: The factors of 98 are 1, 2, 7, 14, 49, 98


Step-by-step explanation:

1 x 98 = 98, 2 x 49 = 98, 7 x 14 = 98, 14 x 7 = 98, 49 x 2 = 98


Hope this helps fren <3

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Resistors are labeled 100 Ω. In fact, the actual resistances are uniformly distributed on the interval (95, 103). Find the mean
Zinaida [17]

Answer:

E[R] = 99 Ω

\sigma_R = 2.3094 Ω

P(98<R<102) = 0.5696

Step-by-step explanation:

The mean resistance is the average of edge values of interval.

Hence,

The mean resistance, E[R] = \frac{a+b}{2}  = \frac{95+103}{2} = \frac{198}{2} = 99 Ω

To find the standard deviation of resistance, we need to find variance first.

V(R) = \frac{(b-a)^2}{12} =\frac{(103-95)^2}{12} = 5.333

Hence,

The standard deviation of resistance, \sigma_R = \sqrt{V(R)} = \sqrt5.333 = 2.3094 Ω

To calculate the probability that resistance is between 98 Ω and 102 Ω, we need to find Normal Distributions.

z_1 = \frac{102-99}{2.3094} = 1.299

z_2 = \frac{98-99}{2.3094} = -0.433

From the Z-table, P(98<R<102) = 0.9032 - 0.3336 = 0.5696

5 0
3 years ago
You and a friend are playing a best-of-three series (first to win 2 games wins the series). You are a stronger player and have a
mariarad [96]

Answer and Step-by-step explanation:

Given that probability of you winning each game = 0.68

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also his chance of winning next game = 0.73

To find probability that you would win the series given that you need to win two games to win the series

= probability that you win first game and second game+ probability that you win first game, lose second game and win third game + probability that you lose first game, win second game and win third game

= 0.68*0.81+0.68*0.32*0.68+0.32*0.68*0.81

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Therefore probability that you would win the series = 0.8750

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Answer:

where is the figure?

Step-by-step explanation:

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Math help (Tan) + brainy
levacccp [35]
Tan = opposite / adjacent
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3 years ago
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Find AB, given that line AD is the perpendicular bisector of BC
astraxan [27]

Answer:

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