Line AB contains points A(4, 5) and B(9.7). What is the slope of AB?

Mathematics

1 answer:

Serggg [28]3 years ago

7 0

Answer: 2/5

Step-by-step explanation:

line up the points and label them XYX2 and Y2. Then subtract X2 minus X1 below Y2 minus Y1 then you will get the slope. In this case it is 2/5 .

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Papessa [141]

Answer:

d = 10/72

Step-by-step explanation:

c and d vary inversely

c = k/d

Where,

k = constant of proportionality

d = 2/9 when c = 5

c = k/d

5 = k ÷ 2/9

5 = k × 9/2

5 = 9k/2

Cross product

5*2 = 9k

10 = 9k

k = 10/9

c = k/d

c = 10/9 ÷ d

c = 10/9 × 1/d

c = 10/9d

find d when c = 8

c = 10/9d

8 = 10/9d

Cross product

8*9d = 10

72d = 10

d = 10/72

8 0

3 years ago

Write the equation of a line that is parallel to y=0.6x+3 and that passes through the point

a_sh-v [17]

A line parallel to y = 0.6x + 3 will be of the form:

$y = 0.6x + k$

where k is a constant.

It passes through (-3,-5)

Thus,

$y = 0.6x + k \\ \\ -5 = 0.6 \times (-3) + k \\ \\ -5 = -1.8 + k \\ \\k = -5 + 1.8 \\ \\ k = -3.2$

$\textbf{The equation is \: \: y = 0.6x - 3.2}$