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natita [175]
3 years ago
9

The volume of the box below is 1.5 cubic inches. Which of the following are possible dimensions of the box.

Mathematics
1 answer:
anygoal [31]3 years ago
7 0
I’m not sure what u mean?
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Factor each trinomial. Then match the polynomial (term) on the left with its factored form (definition) on the right.
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<span>x2 – 4x – 12 A) (x – 6)(x + 2) x2 + 4x – 12 B) Prime x2 – x – 12 C) (x – 4)(x + 3) x2 – 7x – 12 D) (x – 2)(x + 6) i think this is the awnser:)</span>
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3 years ago
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Need steps on how to factor 3x^4 + x^3 + 6x^2 + 2x
ella [17]

Answer:

3x times 3x times 3x times 3x + x^3 + 3x times 2x times 3x times 2x + 2x

or

x^3 + 2x^3 + 3x^6

Step-by-step explanation:

3x^4 + x^3 + 6x^2 + 2x

3x times 3x times 3x times 3x + x^3 + 6x times 6x + 2x

3x times 3x times 3x times 3x + x^3 + 3x times 2x times 3x times 2x + 2x

x^3 + 2x^3 + 3x^6

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3 years ago
Please help me do #59
Svetach [21]

Answer:

So the perimeter is 2(16+x) or 32+2x. The area is 8(x+8) or 8x+64.

Step-by-step explanation:


8 0
3 years ago
A cylindrical container's lateral surface is to be covered by a label. The container's diameter is 5 inches, and its height is 8
Nezavi [6.7K]

Answer:

The correct option is C. 126 in²

Step-by-step explanation:

Diameter of the container = 5 inches

⇒ radius of the container = 2.5 inches

Height of the container = 8 inches

To find how much paper is needed to create the label : We need to find the lateral surface area of the cylindrical shaped container

Lateral Surface Area of Cylinder = 2·π × radius × height

                                                      = 2 × 3.14 × 2.5 × 8

                                                      = 125.66 square inches

                                                      ≈ 126 square inches

Hence, 126 square inches of paper is needed to create the label.

So, The correct option is C. 126 in²

3 0
3 years ago
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Does anyone know how to Graph f(x)=51(2)^x
3241004551 [841]
This is an exponential function.   

If x = 0, 2^x = 2^0 = 1.  The beginning value of 2^x is 1 and the beginning value of 51*2^x is 51.

Make a table and graph the points:

x        y=51*2^x                                point (x,y)
--       ---------------                            ---------------
0             51                                       (0,51)
2            51*2^2 = 51(4) = 204           (2,204)             and so on.

The graph shows up in both Quadrants I and II.  Its y-intercept is (0,51).  Its slope is always positive.

5 0
3 years ago
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