Answer:
Now, 3x 2+x+5⩾0
This is because b² −4ac=1−4×5×3
=−59 (roots are imaginary)
3x²+x+5=(x−3)² =x²+9−6x and x−3⩾0
2x²+7x−4=0
2x²+8x−x−4=0
2x(x+4)−1(x+4)=0
(2x−1)(x+4)=0
x= 1/2 and−4 but x≥3
∴ No solution.
lol hehehe
A'(-9,4)
B'(-4,4)
C'(0,-4)
D'(-5,-4)
Forgive me if I am wrong but it should be 15 hours. If she only studies 1/3 an hour a night it would take 3 1/3 nights so you'd just multiply 3 by 5. If that makes any sense. Sorry not to good at explaining things ;(
Notice the "x" and "y" coordinates
the x-coordinate is well, the cosine value
the y-coordinate is well, the sine value
now the tangent