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3 years ago

How many solutions does the equation have 4x + 3=2(2x +9)

Mathematics

1 answer:

lbvjy [14]3 years ago

6 0

I guess no solution
4x +3 = 4X + 18
4X - 4X = 18 - 3
0 = 15

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Lisa is painting a fence that is 26 feet long and 7 feet tall. A gallon of paint will cover 350 square feet. Write and solve a p

azamat

You first have to multiply 26 by 7 ft which gives you 182 ft then divide 350 by 182 which is 0.52 gallons. your final answer is 0.52 gallons

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3 years ago

Given that (-8,-5) is on the graph of f(x), find

Lemur [1.5K]

Answer:

(-6,-5)

Step-by-step explanation:

Let a function be f(x)

So, f(x-a) would be the same function BUT translated a units to the RIGHT.

So, that changes all x coordinates a units to the right (+a) and all the y-ccordinates remains same.

Our function goes through the transformation f(x-2), which means 2 units to the right, so we "ADD" 2 to all x-coordinates and y remains same.

Thus, the point (-8,-5) would become (-8+2,-5) = (-6,-5)

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3 years ago

I HAVE 2 MORE QUESTIONS AFTER THIS 20 POINTSSS!

ioda

Answer:

Step-by-step explanation:

you have to do 49000 - 8200 which is 40800, and in scientific notation, that is 4.08 * 10^4

3 0

2 years ago

Read 2 more answers

Is anyone able to figure this out, I can't do this

katrin [286]

Answer:

C. √2 - 1

Step-by-step explanation:

If we draw a square from the center of the large circle to the center of one of the small circles, we can see that the sides of the square are equal to the radius of the small circle (see attached diagram)

Let r = the radius of the small circle

Using Pythagoras' Theorem $a^2+b^2=c^2$

(where a and b are the legs, and c is the hypotenuse, of a right triangle)

to find the diagonal of the square:

$\implies r^2 + r^2 = c^2$

$\implies 2r^2 = c^2$

$\implies c=\sqrt{2r^2}$

So the diagonal of the square = $\sqrt{2r^2}$

We are told that the radius of the large circle is 1:

⇒ Diagonal of square + r = 1

$\implies \sqrt{2r^2}+r=1$

$\implies \sqrt{2r^2}=1-r$

$\implies 2r^2=(1-r)^2$

$\implies 2r^2=1-2r+r^2$

$\implies r^2+2r-1=0$

Using the quadratic formula to calculate r:

$\implies r=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

$\implies r=\dfrac{-2\pm\sqrt{2^2-4(1)(-1)}}{2(1)}$

$\implies r=\dfrac{-2\pm\sqrt{8}}{2}$

$\implies r=-1\pm\sqrt{2}$

As distance is positive, $r=-1+\sqrt{2}=\sqrt{2}-1$ only

5 0

2 years ago

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Find the values of the variables and the lengths of the sides of this kite.

TEA [102]

Y=3 , x=-5, x=5/3 , x=10

8 0

2 years ago