write in point slope from an equation of the line that passes through the point (9,7) with slope of 5
1 answer:
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Answer:
26.75
Step-by-step explanation:
There are two ways to do this. You can use the base*height/2 formula for the area of the triangle, or use the complex formula of determining triangle area without height.
The first is A=(b*h)/2
In this case you need to find the height using a²+b²=c²
Take your base (7.6) and divide it by 2 this will give you the bottom side of your triangle (3.8) now plug this, and the side value of 8 into the formula. Remember c is the hypotenuse (diagonal side) and x is the height.
3.8²+x²=8²
14.44+x²=64
x²=49.56
x=7.039 -now you have the height for the triangle and can use this to find the area
A=b*h (in this case we dont have to divide by two since we need two triangles because we split the original in two to find the base of 3.8)
so it's 3.8*7.039=26.75
(If you need more help look up Silicon Valley High school's video titled, "How to find the area of a triangle (without the height)"
It will teach you the formula which teaches you to find the area of any triangle when all you are given is three sides
Answer:
x = 125
Step-by-step explanation:
Tangents from an external point to a circle are congruent , that is
CA = CB
Then Δ ABC is isosceles with base angles being congruent
∠ BAC = ∠ ABC = =
= 55°
∠ ABC and x are adjacent angles on a straight line and sum to 180° , so
x = 180° - 55° = 125°
Then x = 125