Question

Solve the system of equations below: 5x-2y=18 3x+3y=15

Answer 1

Answer : The value of x and y is, 4 and 1 respectively.

Step-by-step explanation :

The given equations are:

$5x-2y=18$       ..........(1)

$3x+3y=15$       ..........(2)

Using substitution method,

$5x-2y=18$

$5x=18+2y$

$x=\frac{18+2y}{5}$      ...........(3)

Now putting equation 3 in 2, we get the value of y.

$3x+3y=15$

$3(\frac{18+2y}{5})+3y=15$

$(\frac{54+6y}{5})+3y=15$

$54+6y+15y=75$

$6y+15y=75-54$

$21y=21$

$y=1$

Now putting value of y in equation 3, we get the value of x.

$x=\frac{18+2y}{5}$

$x=\frac{18+2\times 1}{5}$

$x=\frac{18+2}{5}$

$x=4$

Thus, the value of x and y is, 4 and 1 respectively.

Answer 2

X = 4

y = 1

I hope this helps. :)