Answer:
Answer:
safe speed for the larger radius track u= √2 v
Explanation:
The sum of the forces on either side is the same, the only difference is the radius of curvature and speed.
Also given that r_1= smaller radius
r_2= larger radius curve
r_2= 2r_1..............i
let u be the speed of larger radius curve
now, \sum F = \frac{mv^2}{r_1} =\frac{mu^2}{r_2}∑F=
r
1
mv
2
=
r
2
mu
2
................ii
form i and ii we can write
v^2= \frac{1}{2} u^2v
2
=
2
1
u
2
⇒u= √2 v
therefore, safe speed for the larger radius track u= √2 v
It would be 2u3+4u2-2u-4u2-8u+4= 2u3-10u+4
Using the unit circle, the coordinates of 3π/4 is :
![(-\frac{\sqrt[]{2}}{2},\frac{\sqrt[]{2}}{2})](https://tex.z-dn.net/?f=%28-%5Cfrac%7B%5Csqrt%5B%5D%7B2%7D%7D%7B2%7D%2C%5Cfrac%7B%5Csqrt%5B%5D%7B2%7D%7D%7B2%7D%29)
Note that tangent function can be solved using the formula y/x
where x and y are the coordinates of the angle.
This will be :
![\frac{\sqrt[]{2}}{2}\div(-\frac{\sqrt[]{2}}{2})=-1](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B%5D%7B2%7D%7D%7B2%7D%5Cdiv%28-%5Cfrac%7B%5Csqrt%5B%5D%7B2%7D%7D%7B2%7D%29%3D-1)
The answer is -1
