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ss7ja [257]
3 years ago
7

A motorcycles rider is in the air for 2.5 seconds. Your camera can take a picture every 0.125 second. Your friend's camera can t

ake a picture every 0.15 second. A. How many times faster is your camera than your friend's camera? B. How many more pictures can you take while the rider is in the air? Show your work.
Mathematics
1 answer:
liq [111]3 years ago
5 0
Your camera is not faster than ur friends the difference is 0.015
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Mice21 [21]

Given:

The number is \sqrt{-11}.

To find:

The a+bi form of given number.

Solution:

We have,

\sqrt{-11}

It can be written as

\sqrt{-11}=\sqrt{-1\times 11}

\sqrt{-11}=\sqrt{-1}\times \sqrt{11}      [\because \sqrt{ab}=\sqrt{a}\sqrt{b}]

\sqrt{-11}=i\times \sqrt{11}      [\because \sqrt{-1}=i]

\sqrt{-11}=\sqrt{11}i

Here, real part is missing. So, it can be taken as 0.

\sqrt{-11}=0+\sqrt{11}i

So, a = 0 and b=\sqrt{11}.

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2 years ago
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andriy [413]

Answer:

Step-by-step explanation:

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2x( x + 1) + 7 (x + 1) = 0

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Evaluate the expression -3+2× if the value of x = -2 i got answer -7
seraphim [82]

Answer:

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Yep you were right!

Step-by-step explanation:

-3+2(-2)

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-7

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