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klio [65]
3 years ago
12

Powers of products and quotients. simplify (7y^4)^2

Mathematics
1 answer:
Semenov [28]3 years ago
5 0
The answer simplified is 49y^8
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Which graph can be used to find the solution(s) to x^2-1=3?
olga2289 [7]

First of all, you need to attach images for this one. Second of all, graph it in desmos and compare. Thirdly, whichever looks like this.


6 0
3 years ago
Read 2 more answers
The length of a rectangle is 8feet less than the width. The perimeter is 64 feet. Find the length and the width
nataly862011 [7]

Answer:

Length = 4 feet

Width = 4 feet

Step-by-step explanation:

The perimeter of a rectangle formula = 2L + 2W

Where L = Length

W = Width

The length of a rectangle is 8feet less than the width.

Hence,

L = 8 - W

The perimeter is 64 feet.

Hence,

64 = 2(8 - W) × 2W

64 =( 16 - 2W )2W

64 = -4W² + 32W

4W² - 32W + 64 = 0

Factorise

4W² - 16W - 16W + 64 = 0

4W (W - 4) - 16(W - 4) = 0

W - 4 = 0

W = 4

Width = 4

Solving for L

L = 8 - W

L = 8 - 4

L = 4

Therefore,

Length = 4 feet

Width = 4 feet

7 0
3 years ago
What should be done to solve the equation?
stellarik [79]

Answer:

add 17 to both sides

Step-by-step explanation:

as it cancels itself

mark brainliest

5 0
3 years ago
I Need Help Pleaseeeee
kicyunya [14]
What is the question
3 0
3 years ago
The lengths of the diagonals of a rhombus are 2x and 10x. What expression gives the perimeter of the rhombus?
True [87]

Answer:

P=4x\sqrt{26}\ units

Step-by-step explanation:

we know that

The sides of a rhombus are all congruent and the diagonals are perpendicular bisectors of each other

so

Applying the Pythagorean Theorem

c^2=a^2+b^2

where

c is the length side of the rhombus      

a and b are the semi-diagonals

we have

a=2x/2=x\ units\\b=10x/2=5x\ units

substitute the values

c^2=x^2+(5x)^2

c^2=26x^2

c=x\sqrt{26}\ units

To find out the perimeter of the rhombus multiply the length side by 4

P=(4)(x\sqrt{26})

P=4x\sqrt{26}\ units

6 0
3 years ago
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