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Bas_tet [7]
2 years ago
5

In circle O, what is m∠MAJ? °

Mathematics
1 answer:
mr_godi [17]2 years ago
4 0

See the attached figure.

m ∠KAJ = 170° &  m ∠LAM = 80°

We should know that :

m ∠KAJ + m ∠LAM + m ∠KAL + m ∠MAJ = 360°

∴ m ∠KAL + m ∠MAJ = 360° - (m ∠KAJ + m ∠LAM)

∴ m ∠KAL + m ∠MAJ = 360° - (170°+80°) = 360° - 250° = 110°

But : m ∠KAL = m ∠MAJ ⇒⇒⇒ <u>Opposite angles.</u>

∴ m ∠MAJ + m ∠MAJ = 110°

∴ 2 * m ∠MAJ = 110°

∴ m ∠MAJ = 110° ÷ 2 = 55°


<u>So, the answer is :  m ∠MAJ = 55°</u>

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Step-by-step explanation:

The equation x=\sqrt{6x+7} can be solved by squaring both sides:

x^2 = 6x + 7\\\\x^2 - 6x - 7 = 0\\\\(x-7)(x+1) = 0

We can see that -1 and 7 are solutions, but make sure they are not extraneous by substituting them in the original equation:

1 = \sqrt{-1}\\ 7 = \sqrt{49}

The square root of 49 equals 7, but the square root of -1 is an imaginary number.

The correct choice is <em>"7 is a solution to the original equation. The value –1 is an extraneous solution."</em>

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3 years ago
a woman 1.65. tall stood 50m away from the foot of a tower,and observe that the angle of elevation of the top of the tower to be
ElenaW [278]

\sf\huge\underline{\star Solution:-}

\rightarrowLet the women's height be AE and distance between the women and tower be AC.

Also let the height of tower be BC.

\rightarrowNow, clearly it is forming a triangle.

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\rightarrow\sf{Tan50° \:= \: \frac{BC}{AC}}

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\rightarrow\sf{1.19 ×50\:= \: BC}

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Therefore, total height of the tower =\sf\purple{ 61.15m.}

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Hope it helps you:)

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2 years ago
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FREE BRAINLIEST!! ill also answer questions that you have posted if you answer correctly!!!! (42pts)
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<em>Answer:</em>

∠WVR = 156

<em>Step-by-step explanation:</em>

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Alternate Angle Theorem

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24 - 180 = - ∠WVR

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