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3 years ago

How are common denominator and a common multiple alike and different

1 answer:

6 0

East common multiple is the smallest multiple both numbers can go into. (Example: the LCM of 10 and 4 is 20, because both 10 and 4 go into 20 and 20 is the smallest number both 10 and 4 can go into. You could just multiply them both, but you'd get 40 and since its a bigger number it would be harder to work with.)

Least common denominator is just the least common multiple as a denominator. (Example: if you wanted to find the LCD of 5/7 and 1/10, you'd have to find the LCM of the demoniators (7 and 10) and then just use that as the denominator when adding fractions with unlikely denominators.) Sorry for such a long answer :P

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El numero 38 es par o impar<br> El numero 35 es par o impar?

lara [203]

38 es par 35 es par eso es todo?

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3 years ago

Read 2 more answers

Select the graph that does not represent two quantities in a proportional relationship.

Lerok [7]

The answer is b since it does not touch the origin! (0,0)

5 0

2 years ago

28, 45, 12, 34, 36, 45, 19, 20

Alborosie

1) Mean of the set of data: 29.88

2) Mean absolute deviation: 10.13

3) See explanation

Step-by-step explanation:

The mean of a set of data it is calculated as

$\bar x = \frac{1}{N}\sum x_i$

where

N is the number of data in the set

$x_i$ is the value of each point in the dataset

For the set of data in this problem, we have:

$x_i =[28, 45, 12, 34, 36, 45, 19, 20]$

And the number of values is

N = 8

Therefore, we can calculate the mean:

$\bar x = \frac{1}{8}(28+ 45+ 12+ 34+ 36+ 45+ 19+ 20)=\frac{239}{8}=29.88$

The mean absolute deviation of a set of data is given by

$\delta = \frac{1}{N}\sum |x_i-\bar x|$

where

N is the number of values in the dataset

$x_i$ are the single values

$\bar x$ is the mean of the dataset

The dataset here is

$x_i =[28, 45, 12, 34, 36, 45, 19, 20]$

The mean, calculated in part 1), is

$\bar x = 29.88$

And

N = 8

Therefore the mean absolute deviation is

$\delta = \frac{1}{8}(|28-29.88|+|45-29.88|+|12-29.88|+|34-29.88|+|36-29.88|+|45-29.88|+|19-29.88|+|20-29.88|)=\frac{81}{8}=10.13$

The mean of a dataset is the sum of the single values of the dataset divided by the number of values. The mean represents the value $\bar x$ for which, if the dataset would have N values all equal to $\bar x$ , the sum of the values of the dataset would be the same as the sum of the actual values.

The mean absolute deviation for a set of data represents the average of the absolute deviations of the single points from the mean of the dataset. This quantity gives a measure of the "dispersion" of the points around the mean: in fact, the larger the mean absolute deviation is, the more the points are "spread" around the mean of the dataset. Instead, if the mean absolute deviation is small, it means that the points are closer to the mean value.

Learn more about mean and spread of a distribution:

brainly.com/question/6073431

brainly.com/question/8799684

brainly.com/question/4625002

#LearnwithBrainly

7 0

3 years ago

Explain how you I got 0.16

dybincka [34]

So whats the question?

4 0

3 years ago

Explain the relationship between an equation in exponential form and the equivalent equation in logarithmic form.

Eddi Din [679]

$\bf 
log_{{ a}}{{ b}}=y \iff {{ a}}^y={{ b}}\qquad\qquad 
% exponential notation 2nd form
{{ a}}^y={{ b}}\iff log_{{ a}}{{ b}}=y\\
\\ \quad \\
thus\\
----------------------------\\
8^5=32768\qquad \iff\qquad log_8(32768)=5$

so... notice the example there, with 8
so.. you tell us, what is the relationship then?

8 0

3 years ago