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Shalnov [3]
3 years ago
14

Farouc Jaffer.

Mathematics
1 answer:
harkovskaia [24]3 years ago
6 0

Answer:

1996.66.......

Step-by-step explanation:

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I need help with this question
MrMuchimi
Part a:
this is really just intuition. you can go either way as long as you back up what you say.
either you think hunter would be faster because he starts out with a lot more money, or you think amado would be faster because he earns a lot more.

part b:
let x be the number of hours hunter works, and y the number that amado works.
they both need to earn 600 dollars.

hunter's money is modelled by 150 + 7.5x
to get 600 dollars
150 + 7.5x = 600
7.5x = 450
x = 60

amado's money is modelled by 12y
to get 600 dollars
12y = 600
y = 50

hunter would need to work 60 hours to make enough money, but amado would only need to work 50, so hunter will take longer.

then say whether this agrees with what you guessed in part a
6 0
3 years ago
Matilda has been studying exponential functions in her algebra class and has started to notice a pattern.
dlinn [17]

Answer:

Most likely C

Step-by-step explanation:

This is most likely C because it always goes up and although a and c are the only ones with positive equations a makes you multiply by a decimal which can reduce the number so it's most likely C

4 0
3 years ago
What is the difference?<br> -6-(11)<br> 1-17<br> -5<br> O 5<br> 017
Roman55 [17]

Answer:

-17

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Help please! Complete the proof!
Dmitry [639]
Since CM is perpendicular to AB, it follows that ∠1 and <span>∠2 are 90 degrees.  Since they both have 90 degree angles, that must mean they are both right triangles.

And since </span>∠3 = ∠4 and ∠1 = ∠2, then it follows that ∠A = <span>∠B.  (You can show this by showing that they must add up to 180 degrees.)

So since both right triangles have 3 congruent angles to each, then that makes them similar by AAA (angle angle angle).</span>
5 0
3 years ago
What's 4/6 in decimal form
saw5 [17]
0.66666667 is the answer
3 0
3 years ago
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