The answer to this question is a
Answer:
There is not enough info to draw valid conclusion
Step-by-step explanation:
Hope this helps
Answer:
The force is 12 N
Step-by-step explanation:
* Lets explain how to solve the problem
- Direct variation is a relationship between two variables that can
be expressed by an equation in which one variable is equal to a
constant times the other
- If y ∝ x , then y = kx , where k is the constant of variation
* Lets solve the problem
- The force acting on the object varies directly with the object's
acceleration
∵ The force is F in newtons and a is the acceleration is m/s²
∴ F ∝ a
∴ F = ka
- To find k substitute F and a by the initial values of them
∵ A force of 10 N acts on a certain object, the acceleration of the
object is 5 m/s²
∵ F = 10 N when a = 5 m/s²
∵ F = ka
∴ 10 = k(5)
- Divide both sides by 5
∴ K = 2
- Substitute the value of k in the equation
∴ F = 2a
- Lets find the force when the acceleration is 6 m/s²
∵ a = 6 m/s²
∴ F = 2(6) = 12
* The force is 12 N
The slope of the tangent line to the curve at (8, 2) is given by the derivative
at that point. By the chain rule,

Differentiate the given parametric equations with respect to
:


Then

We have
and
when
, so the slope at the given point is
.
The normal line to the same point is perpendicular to the tangent line, so its slope is +4. Then using the point-slope formula for a line, the normal line has equation

Alternatively, we can eliminate the parameter and express
explicitly in terms of
:

Then the slope of the tangent line is

At
, the slope is again
, so the normal has slope +4, and so on.