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Dafna1 [17]
3 years ago
15

(a) Draw the image of PQR after a rotation of 180° about the origin. Label the image P'Q'R' .

Mathematics
2 answers:
Vilka [71]3 years ago
3 0
A - when doing a 180 degree rotation, the coordinates (x,y) would become (-x,-y), in other words, the inverse of the numbers in the x and y places, (-1,2)->(1,-2)
B - when reflecting over the x axis, only the y coordinate inverts, (x,y) becomes (x,-y), (1,-2)->(1,2)
Strike441 [17]3 years ago
3 0

Answer:

Reflection states that it is a transformation representing a flip of a figure. Figures may be reflected in a point, a line, or a plane.

(a)

The coordinates of triangle PQR from the given figure is:

P = (1, -1)

Q = (3 , -2)

R = (3 , -4)

To rotate a figure 180 degrees:

The rule of rotation of 180 degree :

(x, y) \rightarrow (-x , -y)

Apply the above rule on PQR we have;

P(1, -1) \rightarrow P'(1 , -1)

Q(3, -2) \rightarrow Q'(2 , -3) and

R(3, -4) \rightarrow R'(4 , -3)

The label of image P'Q'R' as shown below in the figure:

(b)

The rule of reflection across the x-axis is:

(x , y) \rightarrow (x , -y)

Apply the above rule on PQR triangle we get;

P(1, -1) \rightarrow P''(1 , 1)

Q(3, -2) \rightarrow Q''(3, 2)

R(3, -4) \rightarrow R''(3 , 4)

Label of image P"Q"R" as shown in the figure.

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Answer:

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Step-by-step explanation:

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slega [8]

Answer:

The equation of the parabola that models the path of the long jumper through the air is y = -x^{2}+12\cdot x -27.

Step-by-step explanation:

Mathematically, we know that parabolas are second-order polynomials and every second-order polynomials, also known as quadratic functions, can be constructed by knowing three different points of the curve. The standard form of the parabola is:

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Where:

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y - Height of the long jumper, measured in meters.

a, b, c - Polynomial constants, measured in \frac{1}{m}, dimensionless and meters, respectively.

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The coefficients of the polynomial are, respectively:

a = -\frac{1}{100}, b = \frac{3}{25}, c = -\frac{27}{100}

The equation of the parabola that models the path of the long jumper through the air is y' = -\frac{1}{100}\cdot x^{2}+\frac{3}{25}\cdot x -\frac{27}{100}.

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y = -x^{2}+12\cdot x -27

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The equation of the parabola that models the path of the long jumper through the air is y = -x^{2}+12\cdot x -27.

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Step-by-step explanation:

8x - 11 = 0

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