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Dafna1 [17]
3 years ago
15

(a) Draw the image of PQR after a rotation of 180° about the origin. Label the image P'Q'R' .

Mathematics
2 answers:
Vilka [71]3 years ago
3 0
A - when doing a 180 degree rotation, the coordinates (x,y) would become (-x,-y), in other words, the inverse of the numbers in the x and y places, (-1,2)->(1,-2)
B - when reflecting over the x axis, only the y coordinate inverts, (x,y) becomes (x,-y), (1,-2)->(1,2)
Strike441 [17]3 years ago
3 0

Answer:

Reflection states that it is a transformation representing a flip of a figure. Figures may be reflected in a point, a line, or a plane.

(a)

The coordinates of triangle PQR from the given figure is:

P = (1, -1)

Q = (3 , -2)

R = (3 , -4)

To rotate a figure 180 degrees:

The rule of rotation of 180 degree :

(x, y) \rightarrow (-x , -y)

Apply the above rule on PQR we have;

P(1, -1) \rightarrow P'(1 , -1)

Q(3, -2) \rightarrow Q'(2 , -3) and

R(3, -4) \rightarrow R'(4 , -3)

The label of image P'Q'R' as shown below in the figure:

(b)

The rule of reflection across the x-axis is:

(x , y) \rightarrow (x , -y)

Apply the above rule on PQR triangle we get;

P(1, -1) \rightarrow P''(1 , 1)

Q(3, -2) \rightarrow Q''(3, 2)

R(3, -4) \rightarrow R''(3 , 4)

Label of image P"Q"R" as shown in the figure.

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You know that the slope is the coefficient of x, so the first choice is eliminated right away. Trying the point values in the other equations shows you that they only work for the last choice, as shown above.

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Step-by-step explanation:

The question is as following:

Select the correct answer from each drop-down menu.

Angle θ lies in the second quadrant, and sin θ =3/5.

cos θ = -4/5, -3/5, 3/5, 4/5

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==================================================

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