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2 years ago

9

A square park is surrounded by a sidewalk. Each side of the park has a length of 2 miles. What is the shortest distance travelin

g diagonally across the park?

1 answer:

zhenek [66]2 years ago

7 0

Answer:

B. 2.8

Step-by-step explanation:

Pythagorean theorem

$a^{2} + b^{2} = c^{2}$

$2^{2} + 2^{2} = c^{2}$

$8 = c^{2}$

square root of 8 = c

2.8 = c

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2. JI. has coordinates J(-6, 1) and Z(-4, 3). Find the coordinates of the midpoint.

AleksandrR [38]

Answer:

(- 5, 2 )

Step-by-step explanation:

Given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

( $\frac{x_{1}+x_{2} }{2}$ , $\frac{y_{1}+y_{2} }{2}$ )

Here (x₁, y₁ ) = (- 6, 1) and (x₂, y₂ ) = (- 4, 3) thus

midpoint = $\frac{-6-4}{2}$ , $\frac{1+3}{2}$ ) = ( $\frac{-10}{2}$ , $\frac{4}{2}$ ) = (- 5, 2 )

7 0

2 years ago

In a homicide case 6 different witnesses picked the same man from a line up. The line-up contained 5 men. If the identifications

Vedmedyk [2.9K]

Answer:

since we have 6 witnesses and 5 men so,

therefore the probability that they would pick the same man is $\frac{5}{6} =0.83333$ to 5 decimal places

Step-by-step explanation:

probability is the likelihood of an event occurring or not happening.

6 0

2 years ago

The length of the hypotenuse of a right triangle is 16 inches. If the length of one leg is 5 inches, what is the approximate len

Musya8 [376]

Answer:

15.2 inches

Step-by-step explanation:

a^2 + b ^2= c^2

5^2 + b ^2=16^2

b ^2=256 - 25

√b ^2=√231

b= 15.2 inches

7 0

2 years ago

HELP ME FAST PLZ ❗️.

vfiekz [6]

Answer:

8

Step-by-step explanation:

You use law of sines, and get: AB/sin(53) = 7/sin(44)

You multiply both sides by sin(53), and get:

AB = 7*sin(53)/sin(44)

That means AB is 8.04776679886, which rounds to 8

7 0

3 years ago

The radius of the circle is increasing at a rate of 2 meters per minute and the sides of the square are increasing at a rate of

Lunna [17]

Answer:

Change in area=24 $\pi$ -48

Step-by-step explanation:

Let s will be the side of square and r will be the radius of circle.

Then two given conditions are

1)dr/dt=2 m/s

2)ds/dt=1 m/s

Area enclosed=(Area of square)-(Area of circle)

Area of square= $s^{2}$

Area of circle= $\pi r^{2}$

Area enclosed= $(\pi r^{2})-s^{2}$

dA/dt=2 $\pi$ r(dr/dt)-2s(ds/dt)

At s=24,and r=6

dA/dt=2( $\pi$ )(6)(2)-2(24)(1)

Change in area=24 $\pi$ -48

6 0

2 years ago