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natka813 [3]
3 years ago
6

Given the function g(x) = b(−5x + 1)6 − a , where a ≠ 0 and b ≠ 0 are constants.

Mathematics
1 answer:
mixer [17]3 years ago
4 0
A.
g'(x) = 6b(-5x + 1)^5 (-5)
g'(x) = -30b(-5x +1)^5

g''(x) = -30b(5)(-5x + 1)^4 (-5)
g''(x) = 750b (-5x +1)^4

b.
g(x) = <span>b(−5x + 1)6 − a
when 
g(-x) = b(5x +1)6 - a

c.
</span>g'(x) = -30b(-5x +1)^5 = 0
-5x +1 = 0
x = 15
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