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pashok25 [27]
3 years ago
9

What is the solution set for |-x|=-x

Mathematics
1 answer:
ExtremeBDS [4]3 years ago
5 0

Answer:

Step-by-step explanation:

x=0

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3241004551 [841]

Answer:

helping hand help to write good

5 0
3 years ago
Make the equation 28 x 1/7 = 4 into a division equation<br> PLEASE ANSWER FAST!!!!
Minchanka [31]
4 divided by 1/7 = 28 i believe. sorry if i’m wrong
7 0
3 years ago
let t : r2 →r2 be the linear transformation that reflects vectors over the y−axis. a) geometrically (that is without computing a
tangare [24]

(a) ( 1, 0 ) is the eigen vector for '-1' and ( 0, 1 ) is the eigen vector for '1'.

(b)  two eigen values of 'k' = 1, -1

for k = 1, eigen vector is \left[\begin{array}{c}0\\1\end{array}\right]

for k = -1 eigen vector is \left[\begin{array}{c}1\\0\end{array}\right]

See the figure for the graph:

(a) for any (x, y) ∈ R² the reflection of (x, y) over the y - axis is ( -x, y )

∴ x → -x hence '-1' is the eigen value.

∴ y → y hence '1' is the eigen value.

also, ( 1, 0 ) → -1 ( 1, 0 ) so ( 1, 0 ) is the eigen vector for '-1'.

( 0, 1 ) → 1 ( 0, 1 ) so ( 0, 1 ) is the eigen vector for '1'.

(b) ∵ T(x, y) = (-x, y)

T(x) = -x = (-1)(x) + 0(y)

T(y) =  y = 0(x) + 1(y)

Matrix Representation of T = \left[\begin{array}{cc}-1&0\\0&1\end{array}\right]

now, eigen value of 'T'

T - kI =  \left[\begin{array}{cc}-1-k&0\\0&1-k\end{array}\right]

after solving the determinant,

we get two eigen values of 'k' = 1, -1

for k = 1, eigen vector is \left[\begin{array}{c}0\\1\end{array}\right]

for k = -1 eigen vector is \left[\begin{array}{c}1\\0\end{array}\right]

Hence,

(a) ( 1, 0 ) is the eigen vector for '-1' and ( 0, 1 ) is the eigen vector for '1'.

(b)  two eigen values of 'k' = 1, -1

for k = 1, eigen vector is \left[\begin{array}{c}0\\1\end{array}\right]

for k = -1 eigen vector is \left[\begin{array}{c}1\\0\end{array}\right]

Learn more about " Matrix and Eigen Values, Vector " from here: brainly.com/question/13050052

#SPJ4

6 0
1 year ago
Find the equivalent exponential expression.<br> [(-4)^3]^2
Karolina [17]

Answer:

4096

Step-by-step explanation:

<em><u>Simplify:</u></em>

=((−4)3)2

=((−4)3)*((−4)3)

=((−4)*(−4)*(−4))*((−4)*(−4)*(−4))

=(−4)*(−4)*(−4)*(−4)*(−4)*(−4)

=(−4)6

<em><u>Step by Step:</u></em>

<u><em>((−4)3)2 </em></u>

<u><em>=(−64)2 </em></u>

<u><em>=4096</em></u>

<u><em /></u>

Answer: 4096

<em><u>Hope this helps.</u></em>

4 0
3 years ago
Find the Total surface area of a cone if it's slant height is 21m and diameter of it's base is 24m.
kherson [118]
<h3><u>Answer :- </u></h3>

  • The total surfAce area of cone is <u>1244.57m².</u>

<h3><u>Step-by-step</u><u> </u><u>explanation</u><u> </u><u>:</u><u>-</u><u> </u></h3>

<u>To </u><u>find </u><u>:</u><u>-</u><u> </u>

  • The total surface area of cone..

<h3><u>Solution :- </u></h3>

Given that ,

  • The slant height of the cone = 21m.
  • Diameter of it's base = 24m.

<h3><u>♦</u><u> </u><u>Radius is </u></h3>

<u>=</u>> Diameter / 2

=> 24 / 2

=> 12m

<h3>As we know that , </h3>

<u>Total surface area of cone = πr ( r + L ) .</u>

<h3><u>Where</u><u> </u><u>we </u><u>know</u><u>,</u></h3>

  • π = 22/7
  • r = Radius ( radii )..
  • L = Slant height.

<h3>According to the question :- </h3>

The total surface of cone is,

<u>=> Total surface area = πr { r + L } ..</u>

=  \frac{22}{7}  \times 12 \times (12 + 21)

=  \frac{22}{7}  \times 12 \times 33

= (22 \times 12 \times 33) \div 7

= (726 \times 12) \div 7

= 8712 \div 7

= 1244.57 {m}^{2}

• Therefore , The total surface area of cone is <u>1244.57m².</u>

Hope this helps you :)

8 0
2 years ago
Read 2 more answers
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