What is the solution set for |-x|=-x

PLEASE HELP timed exam pls

3241004551 [841]

Answer:

helping hand help to write good

5 0

3 years ago

Make the equation 28 x 1/7 = 4 into a division equation PLEASE ANSWER FAST!!!!

Minchanka [31]

4 divided by 1/7 = 28 i believe. sorry if i’m wrong

7 0

3 years ago

let t : r2 →r2 be the linear transformation that reflects vectors over the y−axis. a) geometrically (that is without computing a

tangare [24]

(a) ( 1, 0 ) is the eigen vector for '-1' and ( 0, 1 ) is the eigen vector for '1'.

(b) two eigen values of 'k' = 1, -1

for k = 1, eigen vector is $\left[\begin{array}{c}0\\1\end{array}\right]$

for k = -1 eigen vector is $\left[\begin{array}{c}1\\0\end{array}\right]$

See the figure for the graph:

(a) for any (x, y) ∈ R² the reflection of (x, y) over the y - axis is ( -x, y )

∴ x → -x hence '-1' is the eigen value.

∴ y → y hence '1' is the eigen value.

also, ( 1, 0 ) → -1 ( 1, 0 ) so ( 1, 0 ) is the eigen vector for '-1'.

( 0, 1 ) → 1 ( 0, 1 ) so ( 0, 1 ) is the eigen vector for '1'.

(b) ∵ T(x, y) = (-x, y)

T(x) = -x = (-1)(x) + 0(y)

T(y) = y = 0(x) + 1(y)

Matrix Representation of $T = \left[\begin{array}{cc}-1&0\\0&1\end{array}\right]$

now, eigen value of 'T'

$T - kI = \left[\begin{array}{cc}-1-k&0\\0&1-k\end{array}\right]$

after solving the determinant,

we get two eigen values of 'k' = 1, -1

for k = 1, eigen vector is $\left[\begin{array}{c}0\\1\end{array}\right]$

for k = -1 eigen vector is $\left[\begin{array}{c}1\\0\end{array}\right]$

Hence,

(a) ( 1, 0 ) is the eigen vector for '-1' and ( 0, 1 ) is the eigen vector for '1'.

(b) two eigen values of 'k' = 1, -1

for k = 1, eigen vector is $\left[\begin{array}{c}0\\1\end{array}\right]$

for k = -1 eigen vector is $\left[\begin{array}{c}1\\0\end{array}\right]$

Learn more about " Matrix and Eigen Values, Vector " from here: brainly.com/question/13050052

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6 0

1 year ago

Find the equivalent exponential expression. [(-4)^3]^2

Karolina [17]

Answer:

4096

Step-by-step explanation:

Simplify:

=((−4)3)2

=((−4)3)*((−4)3)

=((−4)*(−4)*(−4))*((−4)*(−4)*(−4))

=(−4)*(−4)*(−4)*(−4)*(−4)*(−4)

=(−4)6

Step by Step:

((−4)3)2

=(−64)2

=4096

Answer: 4096

Hope this helps.

4 0

3 years ago

Find the Total surface area of a cone if it's slant height is 21m and diameter of it's base is 24m.

kherson [118]

<h3>Answer :- </h3>

The total surfAce area of cone is 1244.57m².

<h3>Step-by-step explanation :- </h3>

To find :-

The total surface area of cone..

<h3>Solution :- </h3>

Given that ,

The slant height of the cone = 21m.
Diameter of it's base = 24m.

<h3>♦ Radius is </h3>

=> Diameter / 2

=> 24 / 2

=> 12m

Total surface area of cone = πr ( r + L ) .

<h3>Where we know,</h3>

π = 22/7
r = Radius ( radii )..
L = Slant height.

<h3>According to the question :- </h3>

The total surface of cone is,

=> Total surface area = πr { r + L } ..

$= \frac{22}{7} \times 12 \times (12 + 21)$

$= \frac{22}{7} \times 12 \times 33$

$= (22 \times 12 \times 33) \div 7$

$= (726 \times 12) \div 7$

$= 8712 \div 7$

$= 1244.57 {m}^{2}$

• Therefore , The total surface area of cone is 1244.57m².

Hope this helps you :)

8 0

2 years ago

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