Answer:
Area covered by the fences will be 16.1 unit²
Step-by-step explanation:
Let the first parabola is represented by the function f(x) = 6x²
and second parabola by g(x) = x² + 9
point of intersection of the graphs will be determined when f(x) = g(x)
6x² = x² + 9
5x² = 9
x² = 1.8
x = ± 1.34
Now we will find the area between these curves drawn on the graph.
Area = ![\int_{-1.34}^{1.34}[f(x)-g(x)]dx=\int_{-1.34}^{1.34}[6x^{2}-(x^{2}+9)]dx](https://tex.z-dn.net/?f=%5Cint_%7B-1.34%7D%5E%7B1.34%7D%5Bf%28x%29-g%28x%29%5Ddx%3D%5Cint_%7B-1.34%7D%5E%7B1.34%7D%5B6x%5E%7B2%7D-%28x%5E%7B2%7D%2B9%29%5Ddx)
= 
= ![[\frac{5}{3}x^{3}-9x]_{-1.34}^{1.34}](https://tex.z-dn.net/?f=%5B%5Cfrac%7B5%7D%7B3%7Dx%5E%7B3%7D-9x%5D_%7B-1.34%7D%5E%7B1.34%7D)
= ![[\frac{5}{3}(-1.34)^{3}-9(-1.34)-\frac{5}{3}(1.34)^{3}+9(1.34)]](https://tex.z-dn.net/?f=%5B%5Cfrac%7B5%7D%7B3%7D%28-1.34%29%5E%7B3%7D-9%28-1.34%29-%5Cfrac%7B5%7D%7B3%7D%281.34%29%5E%7B3%7D%2B9%281.34%29%5D)
= ![[-4.01+12.06-4.01+12.06]](https://tex.z-dn.net/?f=%5B-4.01%2B12.06-4.01%2B12.06%5D)
= 16.1 unit²
Answer:
2000 = 600 + 2/5x ; 3500 ft
How To Solve:
2000 = 600 + 2/5x
Combine multiplied terms into a single fraction
2000 = 600 + 2/5x
2000 = 600 + 2x/5
Subtract 600 from both sides of the equation
2000 = 600 + 2x/5
2000 - 600 = 600 + 2x/5 - 600
Simplify
Subtract the numbers
1400 = 600 + 2x/5 − 600
Subtract the numbers
1400 = 2x/5
Solution
X = 3500
The y-term is -2y. We know this is the y-term because it is a multiple of the variable y and is not multiplied with any other variables.
A coefficient is a number that a variable is multiplied by. When there is a number followed by a variable, the number is the coefficient.
In this case, the coefficient of the y-term is -2. The coefficient is negative because 2y is being subtracted, meaning the 2 is negative rather than positive.
Hope this helps!
Trey designed 105 games, so he designed 70 more games. The way the question is worded is weird.
