<span>33/532 or approximately 6.2% that both Sue and Jim will get red gumballs.
For the purpose of this problem, going to group the gumballs into 2 sets. Red and anything else. The number of non-red gumballs is
50 + 150 + 100 = 300
The number of red gumballs is 100.
So what's the probability of 2 random picks both being a red gumball. For the 1st pick, it's a simple matter of 100/400 = 1/4.
For the second pick it's slightly more complicated since there's now only 99 red gumballs. So it's
99/399 = 33/133
To get the combined probability, just multiply them together.
33/133 * 1/4 = 33/532 which is approximately 6.2%</span>
Answer:D
Step-by-step explanation:Multiply x and 3x to get 3x^2 which is the first part, then multiply x and -3 to get -3x then and that to 2 times 3x which get you 3x bc -3x + 6x is 3x, and for the last part, multiply 2 and -3 to get -6 so your answer will be 3x^2+3x-6
Answer:
888
Step-by-step explanation:
let the number be n then divide by 8 , that is 
now add 8 to this
+ 8 and finally multiply this by 8 and equate to 952
8( + 8) = 952 ( divide both sides by 8 )
+ 8 = 119 ( subtract 8 from both sides )
= 111 ( multiply both sides by 8 to clear the fraction )
n = 888
the number chosen was 888
The answer would be 9,372,300.
Answer:7
Step-by-step explanation:
