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3 years ago

9

Maddy bought 2 ⅔ pounds of grapes and 1 ⅕ pounds of apples. If she bought bananas that weighed 1 ¼ times as much as the grapes,

how much did the bananas weigh?

1 answer:

spin [16.1K]3 years ago

4 0

Answer:

3 whole number, 1/3

Step-by-step explanation:

To solve this, Multiply the value of the banana to the weight of the Grapes.

Please find the attached file for a comprehensive Solution.

Maths is fun !

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Which matrix represents the solution to the system of equations below?

boyakko [2]

Answer:

The one that's include a rows 2 1 1 2

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3 years ago

Answer this please !

SpyIntel [72]

Answer:

6

Step-by-step explanation:

$\frac{y}{2} =x^{2} -7$

$\frac{a}{2} =2^{2} -7$

$\frac{a}{2} =-3$

$a=-6$

$\frac{b}{2} =1^{2} -7$

$\frac{b}{2} =-6$

$b=-12$

From the calculations above, we learn that line l and the curve intersect at (2, -6) and (1, -12). Next, we will set up a system of linear equations to solve for the slope and the y-intercept of line l.

$-6=2m+b$

$-12=m+b$

$-24=2m+2b$

$18=-b$

$b=-18$

$-12=m-18$

$m=6$

Therefore, the slope of line l is 6.

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1 year ago

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A line through which two points would be perpendicular to the line y = 2/5x - 5/2 ?

uysha [10]

Answer:

Step-by-step explanation:

c

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2 years ago

. The mean width of 12 iPads is 5.1 inches. The mean width of 8 Kindles is 4.8 inches. a. What is the total width of the iPads?

UkoKoshka [18]

Answer:

a) 61.2, b) 38.4 and c) 4.98

Step-by-step explanation:

Given:

The mean width of 12 I-Pads is 5.1 inches.

The mean width of 8 Kindles is 4.8 inches.

Question asked:

a. What is the total width of the I-Pads?

b. What is the total width of the Kindles?

c. What is the mean width of the 12 I-Pads and 8 Kindles?

Solution:

<u>As we know:</u>

<u /> $Mean =\frac{Sum\ of\ observations}{Number\ of\ observations}\\ \\ Mean\ width =\frac{Sum\ of\ width\ of\ all \ I-pad}{Number \ of\ I-pad}$

$5.1=\frac{Sum\ of\ width\ of\ all\ I-pad}{12} \\ \\ By \ cross\ multiplication\\ \\ Sum\ of\ width\ of\ all\ I-pad}=5.1\times1 2\\ \\ Sum\ of\ width\ of\ all\ I-pad}= 61.2$

a) Thus, the total width of the I-Pads are 61.2 inches.

$Mean\ width =\frac{Sum\ of\ width\ of\ all\ Kindles}{Number \ of\ Kindles}$

$4.8=\frac{Sum\ of\ width\ of\ all\Kindles}{8} \\ \\ By \ cross\ multiplication\\ \\ Sum\ of\ width\ of\ all \ Kindles=4.8\times8\\ \\ Sum\ of\ width\ of \ all\ Kindles}=38.4$

b) Thus, total width of the Kindles are 38.4 inches.

Combined width of both I-pad and Kindles = 61.2 + 38.4 = 99.6 inches

Combined number of observations = 12 + 8 =20

Combined mean of width of the 12 I-Pads and 8 Kindles = Combined width of both I-pad and Kindles $\div$ Combined number of observations

Combined mean of width of the 12 I-Pads and 8 Kindles = $\frac{99.6}{20} =4.98\ inches$

c) Thus, the mean width of the 12 I-Pads and 8 Kindles is 4.98 inches.

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3 years ago

One of the parking lot lights at a hospital has a motion detector on it, and the equation (x+10)2+(y−8)2=16 describes the bounda

Pani-rosa [81]

We are given an equation:
$(x+10)^{2} + (y-8)^{2} = 16$

This is an equation of a circle. General form of a circle equation is:
$(x-a)^{2} + (y-b)^{2} = r^{2}$
Where:
a = x coordinate of a center
b = y coordinate of a center
r = radius of a circle

Motion detector can detect person anywhere within a boundary. The greatest distance at which detector can detect is at the edge of a circle. That distance, between detector and edge of circle, is equal to radius.

From the equation we have:
$r^{2} =16 \\ r=4$
The greatest distance at which person can be detected is 4ft.

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3 years ago

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