A vertical asymptote is what you get when you try to divide by 0. To find where you get these, you need to look at the denominator and what values of x will make the denominator equal to 0.
In your denominator, you have (x+7)(x-5)(x-3).
What values of x makes (x+7)(x-5)(x-3)=0?
If x = -7, if x = 5, or if x = 3, then that entire expression will equal zero. (Same idea as when you solve equations by factoring.
Now the only place this can get trickier is if one of those factors — one of (x+7), (x-5), or (x-3) — also appears in the numerator. If that happens, then it’s more involved whether you have an asymptote or not. But that doesn’t happen in this example.
So the short version: Asymptotes happen when you try to divide by zero. Dividing by zero is not a good thing. So you just ask yourself, “What will make the denominator 0?”
Answer:
K=J+6/2
Step-by-step explanation:
J= -2(3-k)
simplify whats in the bracket
J= -6+2k
J+6=2k
Divide both sides by 2
J+6/2=2k/2
2 and 2 will cancel out
remaining K
So, Therefore K=J+6/2
Hope it Helped
his score was increased... so if he is now at 67 and it was increased by 7 so his first grade would have been 60.
1.66333333 because u divide 4.99 by 3 to get the value of one
F(5) is equal to 17.
f(5)= 3(5)+2= 17
