45 guanine, 55 adenines
Every cytosine needs a guanine to be a pair, so that is 45 pairs right there.
100-45 = 55
There should be 55 adenine and thymine pairs to fill in the remaining bases
They have evolved into the best length for their environment.
Answer:
Option C
Explanation:
Given ,
A1 allele is carried by
% people
Let us assume A1 s dominant genotype
This means 
Thus, frequency of allele in the given population is 
It is also given that the population is in Hardy-Weinberg equilibrium thus

Frequency of fruit fly with genotype A2A2 will be

As per Hardy-Weinberg's second equation of equilibrium

Hence, option C is correct
Answer:
B. DR, Dr, Rd, dr
Explanation:
This question involves two genes. Alleles D and R are dominant over alleles d and r. These two genes obey the law of independent assortment as proposed by Gregor Mendel.
Based on the question, a genotype RrDd will produce the following combination of gametes following the process of meiosis:
DR, Dr, dR, dr