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grin007 [14]
3 years ago
7

What is the x intercept?

Mathematics
1 answer:
Aloiza [94]3 years ago
8 0

Answer:

The x-intercepts are where the graph crosses the x-axis, and the y-intercepts are where the graph crosses the y-axis.

Step-by-step explanation:

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What is the ordered pair of y=4.5x
garri49 [273]

Answer:(1,1)

Step-by-step explanation:

y=4.5x

x=y/4.5

put value of x

y=4.5(y/4.5)

y=y

5 0
3 years ago
Let f(x) be defined for any positive integer x greater than 2 as the sum of all prime numbers less than x. For example, f(4)=2+3
blsea [12.9K]

Answer:

f(86)-f(82)

Step-by-step explanation:

well f of 82 = 2 plus _ plus _ plus _ and f of 86 is 2+_+_+_ subtract them

 (A)  3            (B)   4           (C)   47            (D)   59             (E)   83

these are some possible answers so the answer is b, 4

btw, 86-82 = 4 duh

7 0
3 years ago
Read 2 more answers
Determine the value of y when x=15 if y=6 when x =30
Vladimir79 [104]
6+9=15
y+9=x
x=30
y+9=30
y=21
6 0
3 years ago
The International Air Transport Association surveys business travelers to develop quality ratings for transatlantic gateway airp
motikmotik

Answer:

The 95% confidence interval for the population mean rating is (5.73, 6.95).

Step-by-step explanation:

We start by calculating the mean and standard deviation of the sample:

M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{50}(6+4+6+. . .+6)\\\\\\M=\dfrac{317}{50}\\\\\\M=6.34\\\\\\s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{49}((6-6.34)^2+(4-6.34)^2+(6-6.34)^2+. . . +(6-6.34)^2)}\\\\\\s=\sqrt{\dfrac{229.22}{49}}\\\\\\s=\sqrt{4.68}=2.16\\\\\\

We have to calculate a 95% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=6.34.

The sample size is N=50.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

s_M=\dfrac{s}{\sqrt{N}}=\dfrac{2.16}{\sqrt{50}}=\dfrac{2.16}{7.071}=0.305

The degrees of freedom for this sample size are:

df=n-1=50-1=49

The t-value for a 95% confidence interval and 49 degrees of freedom is t=2.01.

The margin of error (MOE) can be calculated as:

MOE=t\cdot s_M=2.01 \cdot 0.305=0.61

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 6.34-0.61=5.73\\\\UL=M+t \cdot s_M = 6.34+0.61=6.95

The 95% confidence interval for the mean is (5.73, 6.95).

4 0
3 years ago
Please help solve the ineaquality x over 3 is < than 3
elena55 [62]
We have an inequation: 
x/3 < 3
⇒ x < 3*3
⇒ x < 9

The final answer is x < 9~
7 0
3 years ago
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