35÷8=4.375 or u could just put 4 but the real answer is 4.375
Error is between steps 4 and 5. It should say:
Step 4: -9x < 27
Now divide by -9
Step 5: x > -3
Note that the inequality changes direction.
When you mean multiply or divide an inequality by a negative number, the inequality changes direction.
For example:
4 < 5
Multiply by -1:
-4 > -5
Another example:
-5 < 0
5 > 0
Solving for v and combining like terms:
10 + v - 17v = 4
- v - v
10 - 16v = 4
-10 -10
-16v = -6
/-16 /-16
<u><em>v = 0.375 or 3/8
</em></u>Hope this helps!
Answer:
see explanation
Step-by-step explanation:
A translation using the vector < 3, - 4 > , means
Add 3 to the x- coordinate and subtract 4 from the y- coordinate, so
M (- 3, - 2 ) → M' (- 3 + 3, - 2 - 4 ) → M' (0, - 6 )
N (- 1, 4 ) → N' (- 1 + 3, 4 - 4 ) → N' (2, 0 )
P (2, 4 ) → P' (2 + 3, 4 - 4 ) → P' (5, 0 )
Q (4, - 2 ) → Q' (4 + 3, - 2 - 4 ) → (7, - 6 )
Answer:
Step-by-step explanation:
With a factor of (t - 1) we know that zero (ground level) is reached at 1 second from an initial height of (0 - 1)(0 - 1)(0 - 11)(0 - 13)/3 = -1•-1•-11•-13 / 3 = 47⅔ meters at t = 0
As we have <em>two </em>factors of (t - 1) we know the track does not go underground at t = 1, but rises again.
At t = 11 seconds, the car has again returned to ground level, but as we only have a single factor of (t - 11) the car plunges below ground level and returns to above ground level at t = 13 seconds due to the single factor of (t - 13)
we can estimate that the car is the deepest below ground level halfway between 11 and 13 s, so at t = 12. At that time, the depth will be about (12 - 1)(12 - 1)(12 - 11)(12 - 13) / 3 = -(11²/3) = - 40⅓ m.
we can estimate that the car is the highest above ground level halfway between 1 and 11 s, so at t = 6s. At that time, the height will be about (6 - 1)(6 - 1)(6 - 11)(6 - 13) / 3 = 5²•-5•-7 / 3 = 291⅔ m.
It's obvious that the roller coaster car had significant initial velocity at t = 0 to achieve that altitude from an initial height of 47⅔ m
