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damaskus [11]
3 years ago
13

Please answer this correctly

Mathematics
1 answer:
goblinko [34]3 years ago
7 0

Answer:

Car: 60%

Motorcycle: 30%

Truck: 10%

Step-by-step explanation:

Car: \frac{12}{12+6+2} =\frac{12}{20} =\frac{60}{100} or 60%

Motorcycle: \frac{6}{12+6+2} =\frac{6}{20} =\frac{30}{100} or 30%

Truck: \frac{2}{12+6+2} =\frac{2}{20} =\frac{10}{100} or 10%

You might be interested in
How many lines of symmetry does a regular polygon with 16 sides have? A. 2 B. 8 C. 32 D. 16
denpristay [2]

Answer:

C. 32

Step-by-step explanation:

There are 16 lines of symmetry passing through the vertex's and another 16 passing through the mid points of the sides

8 0
3 years ago
A point is reflected in the x- axis. The reflected point is (2,1).
Evgesh-ka [11]

Answer:

A. (2,-1) b:2

Step-by-step explanation:

8 0
3 years ago
Joe has one book each for algebra, geometry, history, psychology, Spanish, English and Physics in his locker. How many different
Alisiya [41]

Answer:

There are 35 different sets of 3 books Joe could choose

Step-by-step explanation:

* Lets explain how to solve the problem

- Combination is a collection of the objects where the order doesn't

 matter

- The formula for the number of possible combinations of r objects from

 a set of n objects is nCr = n!/r!(n-r)!

- n! = n(n - 1)(n - 2)................. × 1

Lets solve the problem

- Joe has one book each for algebra, geometry, history, psychology,

 Spanish, English and Physics in his locker

∴ He has <em>seven</em> books in the locker

- He wants to chose <em>three</em> of them

∵ The order is not important when he chose the books

∴ We will use the combination <em>nCr</em> to find how many different sets

  of three books he can choose

- The total number of books is 7

∴ n = 7

∵ He chooses 3 of them

∴ r = 3

∵ 7C3 = 7!/3!(7 - 3)! = 7!/3!(4!)

∴ 7C3=\frac{(7)(6)(5)(4)(3)(2)(1)}{[(3)(2)(1)][(4)(3)(2)(1)]}=35

∴ 7C3 = 35

* There are 35 different sets of 3 books Joe could choose

3 0
3 years ago
Question. 1 :
vovikov84 [41]
<h3>Answer to Question 1:</h3>

AB= 24cm

BC = 7cm

<B = 90°

AC = ?

<h3>Using Pythagoras theorem :-</h3>

AC^2 = AB^2 + BC ^ 2

AC^2 = 24^2 + 7^2

AC^2 = 576 + 49

AC^2 = √625

AC = 25

<h3>Answer to Question 2 :-</h3>

sin A = 3/4

CosA = ?

TanA = ?

<h3>SinA = Opp. side/Hypotenuse</h3><h3> = 3/4</h3>

(Construct a triangle right angled at B with one side BC of 3cm and hypotenuse AC of 4cm.)

<h3>Using Pythagoras theorem :-</h3>

AC^2 = AB^2 + BC ^ 2

4² = AB² + 3²

16 = AB + 9

AB = √7cm

<h3>CosA = Adjacent side/Hypotenuse</h3>

= AB/AC

= √7/4

<h3>TanA= Opp. side/Adjacent side</h3>

=BC/AB

= 3/√7

4 0
2 years ago
The volume of this sphere is 972pi cubic inches. What is its radius?
maria [59]
4/3pi *r3 = 972pi
Divide both side by pi

4/3 *r3 = 972

r3 = 972* 3/4

r3 = 729

r = the square root of 729 to the third power (I don't know if I'm expressing this correctly but answer is 9, hope you get that)

r = 9 that's your answer.

Hope it's correct, appreciate if you could let me know
8 0
3 years ago
Read 2 more answers
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