Answer:
Let P be the external point. O be the origin. join O and P get OP and nearest point on the circle from P be A.
Let Q be the point onthe circle in which, tangent make 90° with radius at Q.
PQ = 8 and OQ = 6
we get a right angled triangle PQO right angled at Q.
so, OP^2 = OQ^2 + PQ^2= 8^2 + 6^2 = 64 + 36 =1==
therefore OP =10cm
we need nearest point from P, which is PA
PA = OP - OA= 10 -6=4cm
The values of x and y are 45 and 8.
<h3>What is a Linear Pair of Angles?</h3>
When two lines meet at a single point, a pair of linear angles is created. If the angles follow the point where the two lines cross, they are considered to be linear. A linear pair's angles add up to 180° in every case.
Given:
Measures of two linear pairs of angles which are of equal measures are 2x and 11y + 2.
As the sum of linear pair of angles is 180°, and if they are of equal measures, each angle must be equal to 90°.
To determine the values of x and y we equate the given angles to 90°.
2x = 90°
⇒ x = 45
And 11y+2 = 90°
⇒ 11y = 90-2 = 88
⇒ y = 8
To know more about linear pairs visit:
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the formula for area of a rectangle is
Area = length x width
since both the length and the width of the rectangle lie on the same x and y axis, we can find the distance between the width and the distance between the length by subtracting
(-4,9) (-4,-3)
these points lie on the same x axis, so they create a vertical line
9-(-3) = 12
12 units is the distance between them
(-4,-3) (-1,-3)
these points lie on the same y axis, so they create a horizontal line
-1-(-4) = 3
3 units is the distance between them
now that we have the length and the width, we can find the area
A = 12 x 3
A = 36 units²
Answer:
M(6,5) and G(2,9)
Step-by-step explanation:
B(3,6)
C(9,4)
m = [(3+9)/2 , (6+4)/2]
= (6,5)
M(5,9)
H(8,9)
G(x,y)
[(x+8)/2 , (y+9)/2]=(5,9)
(x+8)/2 = 5
x+8 = 10
x = 2
(y+9)/2 = 9
y+9 = 18
y = 9
G(2,9)
(Correct me if i am wrong)
