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Ad libitum [116K]
3 years ago
10

Solve ln2x+ln2=0. x=

Mathematics
1 answer:
daser333 [38]3 years ago
5 0

Answer:

1/4

i hope this is the answer you are looking for

Step-by-step explanation:

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Covert 4,400 centimeters to meters
patriot [66]

Answer:

44 meters

Step-by-step explanation:

4400 cm                 1m

-----------   times  --------

m                       100 cm      

4400/100

44 meters

6 0
3 years ago
Read 2 more answers
What is the value of 0.48
Minchanka [31]

Answer: 48% 48/100

depends on what you are asking for

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Use the data set to answer the question. {22,26,28,35,45,63,91} What is the mean absolute deviation (MAD) of the data set? Enter
shtirl [24]

Answer:

mean absolute deviation is 18.85

Step-by-step explanation:

<u>Step 1:</u>-

Given observation values 22,26,28,35,45,63,91

mean (x ) = \frac{22+26+28+35+45+63+91}{7}

mean = 44.28≅ 44

<u>Step2</u>:-

The deviations of the respective observations from the mean (x)

That is x_{i}-x

22-44, 26-44,28-44,35-44,45-44,63-44,91-44

-22, -18 ,-16 ,-9, 1, 19, 47

<u>Step 3:</u>-

The absolute values of the given data

x_{i}-x

modulus of all these values

22,18,16,9.1,19,47

<u>Step 4</u>:-

Mean absolute deviation M.D=∑ \frac{x_{i}  - x }{n}

MAD = \frac{22+18+16+9+1+19+47}{7}

on simplification we get mean absolute deviation is 18.85

6 0
3 years ago
Which subset is the number √15 a part?
inysia [295]
Irrational Numbers :P

7 0
3 years ago
Paul plays a video game that is scored by round . In about 500 rounds his career average is 20 points per round with a standard
DanielleElmas [232]

Answer:

The mean of the sampling distribution is 20 and the standard deviation is 2.89.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Population:

Mean 20, standard deviation of 5.

Sampling distribution:

3 rounds

Mean = 20

s = \frac{5}{\sqrt{3}} = 2.89

The mean of the sampling distribution is 20 and the standard deviation is 2.89.

5 0
3 years ago
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