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3 years ago

Please help you get alot of points

Mathematics

2 answers:

Lorico [155]3 years ago

5 0

The answer u r looking for is* D, $2.85. Hope I’ve helped ;)

tamaranim1 [39]3 years ago

5 0

$19.00

because its 191.01 i dont know OK so he leave a 15% tip right so you subtract that and you get $19.00

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Which inequality represents the graph below s 75

telo118 [61]

Answer:

Top Left

Step-by-step explanation:

Shaded circle means it will be Greater than or equal to or Less then or equal to. The answwers are less that or equal to 75 so s is less than or equal to 75

5 0

3 years ago

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PLEASEE HELPP!! (how many woman were in the theater before these three walked in?)

Sladkaya [172]

Answer:

Step-by-step explanation:

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2 years ago

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Pleaseeeee helppppp

IRINA_888 [86]

Answer:

(a) (6, 2)

Step-by-step explanation:

The system of equations has one of them in y= form, so it lends itself to solution by substitution.

Using the equation for y to substitute into the first equation, we have ...

2x -y = 10

2x -(-1/2x +5) = 10 . . . . . substitute for y

2x +1/2x -5 = 10 . . . . . eliminate parentheses

5/2x = 15 . . . . . . . . . add 5, collect terms

x = 6 . . . . . . . . . . . multiply by 2/5

Using the equation for y, we have ...

y = -1/2(6) +5 = -3 +5

y = 2

The solution is (x, y) = (6, 2).

3 0

2 years ago

Water is placed in a cellular bucket on a bench The book has a diameter of 12 in and a height of 12 in The bucket is capable of

Ilya [14]

Answer:

bucket of water = 50.397 lbs

Step-by-step explanation:

Pi(r^2)(h) = volume

3.14(6^2)(12) = 1356.48 in^3 = volume of bucket

one ft^3 = 12 x 12 x 12 = 1728 in^3

1356.48/1728 = 0.785 ft^3 (volume of bucket)

0.785(64.2) = 50.397 lbs

6 0

3 years ago

With full explanation from the internet like before 3x2-6x+5=0

Elodia [21]

Answer:

$\sf x=1+i\sqrt{\dfrac{2}{3}} \ \quad and \quad \:x=1-i\sqrt{\dfrac{2}{3}}$

Explanation:

Given Expression:

3x² - 6x + 5 = 0

Use the Quadratic Formula:

$\sf x = \dfrac{ -b \pm \sqrt{b^2 - 4ac}}{2a} \ \ when \ \ ax^2 + bx + c = 0$

insert coefficients

$\Longrightarrow \sf x = \dfrac{-\left(-6\right)\pm \sqrt{\left(-6\right)^2-4\cdot \:3\cdot \:5}}{2\cdot \:3}$

$\Longrightarrow \sf x = \dfrac{\left6\right\pm \sqrt{-24} }{6}$

$\Longrightarrow \sf x = \dfrac{\left6\right\pm 2\sqrt{6}i}{6}$

$\Longrightarrow \sf x =1 \pm i\dfrac{\sqrt{6} }{3}$

$\Longrightarrow \sf x=1+i\sqrt{\dfrac{2}{3}}, \quad 1-i\sqrt{\dfrac{2}{3}}$

6 0

2 years ago

Read 2 more answers