Question

Qual o valor que Z assume? -Cz+ 6z = Tz+ 83

Answer 1

Answer:

$\large \boxed{z = \dfrac{83}{6 - C - T}}$

Step-by-step explanation:

$\begin{array}{rccl}-Cz + 6z & = & Tz + 83 & \\6z -Cz - Tz &= & 83 & \text{Subtracted Tz from each side}\\z(6 - C - T) & = & 83 & \text{Removed the common factor}\\z& = & \mathbf{\dfrac{83}{6 - C - T}} &\text{Divided each side by 6 - C - T}\\\end{array}\\\\\large \boxed{\mathbf{z = \dfrac{83}{6 - C - T}}}$