What is the angle addition postulate?

1 answer:

6 0

It states that if you place two angles side by side, then the measure of the resulting angle will be equal to the sum of the two original angle measures.

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Which point lies on the graph of Y= 4x-4<br> 1.(0,4)<br> 2.(0,-4)<br> 3.(-4,0)<br> 4.(4,0)

statuscvo [17]

Answer:

Step-by-step explanation:

$y=4x-4\\\\\text{Substitute the coordinates of each points to the equation}\\\text{and check the equality.}\\\\1.\ (0,\ 4)\to x=0,\ y=4\\\\4=4(0)-4\\4=0-4\\4=-4\qquad\bold{FALSE}\\\\2.\ (0,\ -4)\to x=0,\ y=-4\\\\-4=4(0)-4\\-4=0-4\\-4=-4\qquad\bold{TRUE}\\\\3.\ (-4,\ 0)\to x=-4,\ y=0\\\\0=4(-4)-4\\0=-16-4\\0=-20\qquad\bold{FALSE}\\\\4.\ (4,\ 0)\to x=4,\ y=0\\\\0=4(4)-4\\0=16-4\\0=12\qquad\bold{FALSE}$

5 0

3 years ago

Which equation is correct using "is not equal to'' (≠)?

romanna [79]

65/5=13-3=10 27-17=10

72/6=12-1=11 54-43=11

88/8=11-2=9 27-18=9

90/3=30-8=22 34-10=24

So, that makes "90 ÷ 3 − 8 _____ 34 − 10" not equal.

Hope this helps! Stay Safe!

5 0

3 years ago

If you earn 8 dollars and hour after taxes are taken out of your paycheck and insurance is 200 dollars a month how many hours mu

Luda [366]

To make $200 a month with a 8 dollars p/h salary AFTER taxes. The simple math would just be 200/8 which would equal 25. Hope this helped!

4 0

3 years ago

Carlos completed x3 squats as part of his football workout. if x=5, how many squats did he complete?

omeli [17]

We need to substitute x with 5 because the question is asking how many squats Carlos has completed if he completed 5.

3 x 5 = 15

Therefore, Carlos completed 15 squats as part of his football workout.

By the way, this question is very simple and basic. I recommend reviewing Algebra for your benefit/

5 0

2 years ago

Consider the following set of equations, where s, s0, x and r have units of length, t has units of time, v has units of velocity

Anna11 [10]

Answer:

Step-by-step explanation:

For an equation to be dimensionally correct the dimension of quantities on both sides of equation must be same.

Also, two physically quantities can only be added or subtracted only when their dimension are same.

here all option are dimensionally correct except the 5th option where

dimension of t= [T] whereas dimension of a/v is $\frac{LT^{-2}}{LT^{-1}}$

= T^{-1}

since, the dimension of quantities on either sides of equation are not the same the equation is dimensionally is incorrect.

8 0

3 years ago