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jek_recluse [69]
3 years ago
9

Tim measures the length of four grasshoppers in his backyard: 5/4cm, 7/4cm, 9/4cm, 3/4cm. What is the average length?

Mathematics
1 answer:
hodyreva [135]3 years ago
6 0

Answer:

1.5 cm

Step-by-step explanation:

To find averages, you add up all the values then divide by the amount of number there are (i.e, 6, 7, 8, so there would be three numbers and therefore divide by 3)

You might be interested in
Simplify this expression 5a/11a
barxatty [35]
You could cross cancel the a and your final answer would be 5/11
6 0
4 years ago
Read 2 more answers
Algebra pyramid please answer !! be the first to be marked as a brainliest .
azamat

Answer:

The first pyramid:

      63x

  39x  24x  

23x  16x  8x

The second pyramid:

     162x

 82x  80x  

4x  78x  2x

The third pyramid:

     12a+2b

9a+b   3a+b  

9a     b     3a

The fourth pyramid:

      -19a

  -5a   -14a  

3a   -8a  -6a

   

Step-by-step explanation:

All that an alegbra pyramid is is adding the two terms below it.

So you can see how I added the terms that lied below each number, such as in number 1:  I added 23x and 16x to get me 39x, and I added 16x and 8x to get me 24.

Hope this helped!

4 0
3 years ago
I need help I'm not good at this very much
xeze [42]

Answer:

1- corresponding? 2- alternate interior 3- linear pair 4- alternate exterior 5- vertical 6- alterative exterior?

Step-by-step explanation:

I hope this help sweetie:(

4 0
4 years ago
You have asked to design a rectangle box with a square base and an open top. The volume of the box must be620 cm to the 3rd powe
hammer [34]

Answer:

$69.21

Step-by-step explanation:

Since the box has a square base the length and breadth of the box will be equal. Let it be x

Let h be the height of the box

V = Volume of the box = 620\ \text{cm}^3

x^2h=620\\\Rightarrow h=\dfrac{620}{x^2}

Now surface area of the box with an open top is given

s=x^2+4xh\\\Rightarrow s=x^2+4x\dfrac{620}{x^2}\\\Rightarrow s=x^2+\dfrac{2480}{x}

Differentiating with respect to x we get

\dfrac{ds}{dx}=2x-\dfrac{2480}{x^2}

Equating with zero

0=2x-\dfrac{2480}{x^2}\\\Rightarrow 2x^3-2480=0\\\Rightarrow x^3=\dfrac{2480}{2}\\\Rightarrow x=(1240)^{\dfrac{1}{3}}\\\Rightarrow x=10.74

Double derivative of the function

\dfrac{d^2s}{ds^2}=2+\dfrac{4960}{x^3}=2+\dfrac{4960}{1240}\\\Rightarrow \dfrac{d^2s}{ds^2}=6>0

So, x at 10.74 is the minimum value of the function.

h=\dfrac{620}{x^2}\\\Rightarrow h=\dfrac{620}{10.74^2}\\\Rightarrow h=5.37

So, minimum length and breadth of the box is 10.74 cm while the height of the box is 5.37 cm.

The total area of the sides is 4xh=4\times 10.74\times 5.37=230.7\ \text{cm}^2

The area of the base is x^2=10.74^2=115.35\ \text{cm}^2

Cost of the base is $0.40 per square cm

Cost of the side is  $0.10 per square cm

Minimum cost would be

230.7\times 0.1+0.4\times 115.34=\$69.21

The minimum cost of the box is 69.21 dollars.

8 0
3 years ago
Find the quotient. 12a^3p^4 ÷ -2a^2p
777dan777 [17]

Answer:

-(6ap³)

Step-by-step explanation:

We have to find the quotients of

\frac{12a^{3}p^{4}}{-2a^{2}p}

We take the common 2a² p from the numerator

= \frac{(6ap^{3}(2a^{2}p))}{(-2a^{2}p)}

= -(6ap³)

Therefore, the quotient after division will be -(6ap³)

4 0
3 years ago
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