Answer: 12 yearly admissions and 38 single admissions
Step-by-step explanation:
Let x be yearly membership
Let y be single admission
x+y=50 --> # of tickets sold
35.25x+6.25y=660.50 --> $ of tickets
Use elimination method to solve (multiply equation 1 by -3525 and equation 2 by 100)
-3525x-3525y=-176250
+ 3525+625y=66050
-----------------------------------
-2900y=-110200
y=38
Substitute y=38 into equation 1
x+38=50
x=12
Therefore, 12 yearly admissions and 38 single admissions were sold
Comment
You have to begin by declaring what g(f(x)) means. It means that wherever you see an x in g(x) you put in f(x).
It will look like this to start with
g(f(x)) = (f(x) + 5) / (f(x)
Now substitute into this for g(-3)
g(x^2 + 5) = (x^2 + 5 + 5)/(x^2 + 5) It's time to use some numbers.
g(- 3) = ((-3)^2 + 10)/( (-3)^2 +5)
g(-3) = ( 9 + 10 ) / ( 9 + 5)
g(-3) = (19)/14 <<<<<< answer.
C <<<< answer.
Answer:
88 won and 66 lost
Step-by-step explanation:
Won = 
×4 = 88 games
Lost = 154 - 88 = 66 games
The equation is y = 16/25 x
lets find the proportional relationship,
y = kx
2/5 = k * 5/8
k = (2/5) / (5/8)
k = 16/25
so if k, constant is 16/25
equation is:
y = 16/25 x
<h3>What are proportional relationships?</h3>
Proportional relationships are relationships between two variables where their ratios are equivalent. Another way to think about them is that, in a proportional relationship, one variable is always a constant value times the other. That constant is know as the "constant of proportionality".
<h3>How do you find the proportional relationship in an equation?</h3>
The equation that represents a proportional relationship, or a line, is y = k x , where is the constant of proportionality. Use k = y x from either a table or a graph to find k and create the equation.
To learn more about proportional relationship from the given link
brainly.com/question/2143065
#SPJ4
If 30% were perfect, 70% were not perfect. So we know that 70% of the total number of photographs is 210.
p(70/100)=210 multiply both sides by 100
70p=21000 divide both sides by 70
p=300
So there are 300 photographs in all.
