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erica [24]
3 years ago
13

How to solve for 1000(x-2)=75000

Mathematics
2 answers:
Andrews [41]3 years ago
8 0
So, first you divide 75000 by 1000. Then you add 2 to each side. Then that's the answer, x=77
Nikitich [7]3 years ago
4 0

Answer:

x = 77

Step-by-step explanation:

1000(77-2)=

1000(75)=

75000

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Completely simplified the expression for x plus 10 plus 6 x plus 2 x by combining like terms into your answer in the box.
siniylev [52]
We can first turn the text into a proper formula:

x plus 10 plus 6 x plus 2 x

x+10+6x+2x

The like terms are the numbers with

We can then put the like terms together to continue the calculation:

x+6x+2x+10

=9x + 10

Therefore, the answer is 9x + 10.

Hope it helps!
7 0
3 years ago
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Find 0.45 of 80 A.36 B.3.6 C.0.36 D.0.036
andrew-mc [135]

A

the word 'of' means to multiply

0.45 × 80 = 36


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3 years ago
What is the exponential form of the logarithmic equation?<br> 5 = logo.9 0.59049
galina1969 [7]

^ means to the power of or exponent

logb(x) = y is b^y = x

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3 years ago
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What is 9.375 Rounded to the nearest hundredth
stiks02 [169]

Note the hundredth place value (underlined and bolded):

9.3<u>7</u>5

Look at the number to the right of the hundredth place value. It is a 5. Because you round up if the number is 5 or greater, you round up in this case (you round down if it is 4 or less).

9.375 rounded to the nearest hundredth is 9.38

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3 0
3 years ago
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Solve the following system of linear equations: 3x1+6x2+6x3 = -9 -2x1–3x2-3x3 = 3 If the system has infinitely many solutions, y
choli [55]

Answer:

The set of solutions is \{\left[\begin{array}{c}x\\y\\z\end{array}\right]=\left[\begin{array}{c}12\\-7-r\\r\end{array}\right]: \text{r is a real number}  \}

Step-by-step explanation:

The augmented matrix of the system is \left[\begin{array}{ccccc}3&6&6&-9\\-2&-3&-3&3\end{array}\right].

We will use rows operations for find the echelon form of the matrix.

  • In row 2 we subtract \frac{2}{3} from row 1. (R2- 2/3R1) and we obtain the matrix \left[\begin{array}{cccc}3&6&6&-9\\0&1&1&-7\end{array}\right]
  • We multiply the row 1 by \frac{1}{3}.

Now we solve for the unknown variables:

  • x_2+x_3=-7, x_2=-7-x_3
  • x_1+2x_2+2x_3=-2, x_1+2(-7-x_3)+2x_3=-2 then x_1=12

The system has a free variable, the the system has infinite solutions and the set of solutions is \{\left[\begin{array}{c}x\\y\\z\end{array}\right]=\left[\begin{array}{c}12\\-7-r\\r\end{array}\right]: \text{r is a real number}  \}

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3 years ago
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