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topjm [15]
4 years ago
11

3p-1=5 (p-1)-2 (7-2p)

Mathematics
1 answer:
NikAS [45]4 years ago
3 0
P=2 

3p-1=5p-5-14+4p
3p-1=9p-19
-1=6p-19
18=6p
p=2
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Find the area of the following picture​
lisov135 [29]
Answer = 50


Separate both into two different rectangles

Find the missing sides

Multiply (length x width)

Add the area of both the rectangles together

Example :

Top rectangle

10 - 6 = 4yd

4 x 8 = 32


Bottom rectangle

8 - 5 = 3yd

3 x 6 = 18



Area = 50
3 0
3 years ago
What is the mean of the set of numbers, {–11, 22, –2, –3}? A. –6.5 B. –1.5 C. 1.5 D. 6.5
tekilochka [14]
\dfrac{-11+22+(-2)+(-3)}{4}=\dfrac{22-16}{4}=\dfrac{6}{4}=\fbox{1.5}\to\fbox{C.}
7 0
3 years ago
Read 2 more answers
The potential in a region between x = 0 and x = 6.00 m is V = a + bx, where a = 15.4 V and b = -5.10 V/m.
Minchanka [31]

Answer:

V(0)=15.4\\V(3)=0.1\\V(6)=-15.2

Step-by-step explanation:

The potential in a region between x = 0 and x = 6.00 m is V = a + bx.

Put a = 15.4 V and b = -5.10 V/m.

So, V=15.4-5.10x

To find: Potential at x =0, 3, 6

Solution:

Potential at x = 0:

V=15.4-0=15.4

Potential at x = 3:

V=15.4-5.10(3)=15.4-15.3=0.1

Potential at x = 6:

V=15.4-5.10(6)=15.4-30.60=-15.2

Therefore,

V(0)=15.4\\V(3)=0.1\\V(6)=-15.2

7 0
4 years ago
Please help .............​
Lostsunrise [7]

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AB=AD

AC=AC(common side)

BC=DC

So, ∆ABC and ∆ADC are congruent triangles,

so, m<ABC= m<ADC(corresponding angles of the congruent triangles)

x= 97°

6 0
3 years ago
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Sam had 1 3\16 yards of ribbon. He cut it into Pieces 1\8 of a yard long. How many pieces did he cut?
Semmy [17]
1 3/16 = 19/16

(19/16) / (1/8) = 
19/16 * 8/1 =
152/16 =
9.5 
8 0
3 years ago
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