All categories

3 years ago

(3 × 6) + 4 = 8 + 4 + 32

Mathematics

1 answer:

Sedbober [7]3 years ago

4 0

Answer:

d. false, (3 × 6) + 4 < 8 + 4 + 32

Step-by-step explanation:

We want to determine whether, (3 × 6) + 4 = 8 + 4 + 32 is a true or false statement.

Let us first of all simplify the LHS of given expresion to get:

(3 × 6) + 4 = 18+4=22

The RHS is 8+4+32=12+32=44.

We can see that the LHS is less than RHS.

The correct answer is

d. false, (3 × 6) + 4 < 8 + 4 + 32

You might be interested in

How many weeks are there in 81 days

natima [27]

Answer: At least 8

Reason: A week has 7 days in it, so when you divide 81 by 7, you get 7.5, so when you round it, you get the number 8

If you have any questions, corrections, or problems, let me know. I hope this helped

4 0

2 years ago

TanA+tan(60+A)+tan(120-A)=3tan3A

Volgvan

Answer: not and identity

Step-by-step explanation:

3 0

2 years ago

Write the differential equation model that fits the given description. (a) The rate of change of the volume of a snowball (due t

miskamm [114]

Answer:

a) he rate of change of the volume of a snowball (due to melting) is proportional to the square of the volume at time t. Initially, the snowball has a volume of 900 cm3

$\frac{dV(t)}{dT} = A*V(t)^{2} \\$ and V(0) = 900 $cm^{3}$

where A is a real constant, it appears because it says that the change i volume (dV/dt) is "proportional" to $V(t)^{2}$ . Furthermore, we should assume that A is a negative number, because the volume of the snowball will decrease as the time pasese by.

(b) For an insect moving along some path, the velocity at time t is proportional to the square root of its position.

$\frac{dr(t)}{dt} = B*\sqrt{r(t)}$

Here again appears a constant B for the "proportional" part. And i wrote the velocity as $\frac{dr(t)}{dt}$ "the rate of change of the position with respect to te time".

7 0

3 years ago

Find the area of a quadrilateral ABCD in which AB = 3 cm, BC = 4 cm, CD = 4 cm, DA = 5 cm and AC = 5 cm.

melamori03 [73]

Answer:

$6+2\sqrt{21}\:\mathrm{cm^2}\approx 15.17\:\mathrm{cm^2}$

Step-by-step explanation:

The quadrilateral ABCD consists of two triangles. By adding the area of the two triangles, we get the area of the entire quadrilateral.

Vertices A, B, and C form a right triangle with legs $AB=3$ , $BC=4$ , and $AC=5$ . The two legs, 3 and 4, represent the triangle's height and base, respectively.

The area of a triangle with base $b$ and height $h$ is given by $A=\frac{1}{2}bh$ . Therefore, the area of this right triangle is:

$A=\frac{1}{2}\cdot 3\cdot 4=\frac{1}{2}\cdot 12=6\:\mathrm{cm^2}$

The other triangle is a bit trickier. Triangle $\triangle ADC$ is an isosceles triangles with sides 5, 5, and 4. To find its area, we can use Heron's Formula, given by: