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4 years ago

What are solutions to the equation sinx cosx = square root 3 over4

Mathematics

1 answer:

andrey2020 [161]4 years ago

7 0

$\sin(x)\cos(x)=\dfrac{\sqrt{3}}{4}\\\\2\sin(x)\cos(x)=\dfrac{\sqrt{3}}{2}\\\\\sin(2x)=\dfrac{\sqrt{3}}{2}\\\\2x=\arcsin\left( \dfrac{\sqrt{3}}{2} \right)\\\\2x=\left\{ \dfrac{\pi}{3},\dfrac{2\pi}{3}\right\}+2n\pi\\\\\boxed{x=\left\{ \dfrac{\pi}{6},\dfrac{\pi}{3}\right\}+n\pi}$

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Answer:

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Step-by-step explanation:

Given as :

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i.e y - (-7) = ( 3 ) × ( x - (-2) )

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So, The equation of line is y = 3 x - 1

Hence, The equation of line is y = 3 x - 1 , i.e option A .

And The rate of change = m = 3 Answer

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