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Anna35 [415]
3 years ago
5

Solve please. Fastest + most accurate answer gets brainliest.

Mathematics
2 answers:
asambeis [7]3 years ago
4 0

Answer:

QPR is 47

Step-by-step explanation:

I dont know the rest sorry

Natasha_Volkova [10]3 years ago
4 0

Answer:

m<P = 53

m<Q = 89

m<QRP = 47

Step-by-step explanation:

133= (13y+2) + (8y+5)

133= 21y + 7

126= 21y

Y= 6

13(6)+ 2= 80

8(6)+ 5 = 53

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The graph of the equation y = m^x passes through the point
Alexeev081 [22]

The graph of the equation y = m^x passes through the point (1, m)

<h3>Equation of a graph</h3>

Given the equation of a graph expressed as y = m^x

We need to determine the coordinate point that lies on this graph.

If x = 1, substitute into the formula to have:

y =m^1

y = m

Hence the required coordinate will be (1, m)

Learn more on equation of graph here: brainly.com/question/24894997

3 0
2 years ago
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kompoz [17]

Answer:  c) 2x² - 2x + 4

Step-by-step explanation:

3 0
3 years ago
Please answer correctly! I will mark you Brainliest!
weeeeeb [17]

Answer:

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4 0
3 years ago
Read 2 more answers
The sum of 5 consecutive even numbers is 20
vladimir2022 [97]

Step-by-step explanation:

Let the 1st number be x

2nd number = x + 2

3rd number = x + 4

4th number = x + 6

5th number = x + 8

x + x + 2 + x + 4 + x + 6 + x + 8 = 20

5x + 20 = 20

5x = 20 - 20

5x = 0

x = 0 ÷ 5

x = 0

The 5 consecutive integers are

0, 2, 4, 6, 8

8 0
3 years ago
US average math SAT scores follow a normal distribution with a mean of 505 and a standard deviation of 112. A sample of 64 enter
Hitman42 [59]

Answer:

The claim that the scores of UT students are less than the US average is wrong

Step-by-step explanation:

Given : Sample size = 64

           Standard deviation = 112

           Mean = 505

           Average score = 477

To Find : Test the claim that the scores of UT students are less than the US average at the 0.05 level of significance.

Solution:

Sample size = 64

n > 30

So we will use z test

H_0:\mu \geq 477\\H_a:\mu < 477

Formula : z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}

z=\frac{505-477}{\frac{112}{\sqrt{64}}}

z=2

Refer the z table for p value

p value = 0.9772

α=0.05

p value > α

So, we accept the null hypothesis

Hence The claim that the scores of UT students are less than the US average is wrong

3 0
3 years ago
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