Answer:
35
Step-by-step explanation:
7 orchids can be lined as 7!. This means that for the first orchid of the line, you can select 7 options. When you place the first orchid, for the second option you can select among 6 since 1 orchid has already been placed. Similarly, for the 3rd orchid of the line, you have left 5 options. The sequence goes in this fashion and for 7 orchids, you have 7*6*5*4*3*2*1 possibilities. However, there is a restriction here. 3 of the orchids are white and 4 are levender. This means that it does not make a difference if we line 3 white orchids in an arbitrary order since it will seem the same from the outside. As a result, the options for lining the 7 orchids diminish. The reduction should eliminate the number of different lining within the same colors. Similar to 7! explanation above, 3 white orchids can be lined as 3! and 4 levender orchids can be lined as 4!. To eliminate these options, we divide all options by the restrictions. The result is:
= 35. [(7*6*5*4*3*2*1/(4*3*2*1*3*2*1)]
X = the number of months the tire was used
y = the thickness of the tire tread
y = -(3/7)x + 20
Substitute x for 20 (the number of months the tire was used) and solve for y.
The next question: Substitute x for 49 (the number of months the tire was used) and solve for y.
An angle bisector divides an angle into two equal halves.
The measure of angle
is 70 degrees
The complete question is an illustrates the concept of angle bisector;
Where:
, and line PC bisects 
Because line PC bisects
, then it means that the measure of RPD is twice the measure of CPD:
So, we have:

Substitute 

Divide both sides by 2

Apply symmetric property of equality:

Hence, the measure of angle
is 70 degrees
Read more about angle bisectors at:
brainly.com/question/12896755
15 pounds / 35 sandwiches ~ 0.43 pounds ham per sandwich
We shall first of all, convert all the numbers to the same base. This means we either;
Convert the fractions to decimals OR
Convert the decimals to fractions
Let us therefore convert the decimals to fractions.