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MrRa [10]
3 years ago
12

Solve for f -f+2+4f=8-3f

Mathematics
2 answers:
Fed [463]3 years ago
4 0
In a step by step fashion you solve the problem like so:

Move terms:
3f+2=8-3f

Combine like terms:
3f+3f=8-2

Divide
6f=6

Solution
f=1
yKpoI14uk [10]3 years ago
4 0
Combine like terms on each side: 3f + 2 = 8 - 3f
Move like terms to the same side:
3f + 3f = 8 - 2
Combine:
6f = 6
Divide 6 off of the f on both sides
6f = 6
— —
6 6
f = 1
You might be interested in
Emelina wrote the equation of a line in point-slope form as shown below. (y+4)=3(x+2) What is Emelina’s equation in slope-interc
Sergeeva-Olga [200]

Answer:

y=3x+2

Step-by-step explanation:

We are given equation as

(y+4)=3(x+2)

Since, we have to write equation in slope-intercept form

so, we can use slope-intercept formula

y=mx+b

where m is a slope

b is y-intercept

so, we can write our equation in this form

(y+4)=3(x+2)

Distribute 3

y+4=3\times x+3\times 2

y+4=3x+6

Subtract both sides by 4

y+4-4=3x+6-4

y+4-4=3x+6-4

y=3x+2

So, slope-intercept form of equation is

y=3x+2


4 0
3 years ago
Read 2 more answers
What is the product of one half and two thirds?
attashe74 [19]

Answer:

1/4

Step-by-step explanation:

1/2 × 2/3

= 1×3 = 1

2×2 = 4

Therefore,

1/2 × 2/3 = 1/4//

4 0
3 years ago
When utilizing ANOVA, what does the between group sum of squares measure?
zhenek [66]

Answer:

b. The sum of the squared deviations between each group mean and the mean across all groups

Step-by-step explanation:

Previous concepts

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"

Solution to the problem

If we assume that we have p groups and on each group from j=1,\dots,p we have n_j individuals on each group we can define the following formulas of variation:  

SS_{total}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x)^2

SS_{between}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2

SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2

And we have this property

SST=SS_{between}+SS_{within}

As we can see the sum of squares between represent the sum of squared deviations between each group mean and the mean across all groups.

SS_{between}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2

So then the best option is:

b. The sum of the squared deviations between each group mean and the mean across all groups

5 0
3 years ago
20 POINTS!!
yaroslaw [1]
This is the answer. I did it and got that. You do distributive and then combine like terms.

7 0
4 years ago
Help on number 1 is needed!!
tamaranim1 [39]

Answer:

Substitute the values given for f(x) and g(x), in 1. they say f(x)=4x and g(x)=1-x

and basically just substitute them for the functions themselves.

4x+1-x

add like terms!

4x-x = 3x!

3x+1 is your simplified answer, since it is an expression it cannot be simplified any further.

7 0
3 years ago
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