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kogti [31]
3 years ago
10

Is there more than one way to get 2/3/4/5 to the simplest form

Mathematics
1 answer:
seropon [69]3 years ago
4 0
Multiply 2 and 3 also multiply 4 and 5 and then divide the products together like so 2x3 divided by 4x5   so 6 divided by 20
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Josh bought 6 pounds of sugar for $4. How many pounds of sugar did he get per dollar?
Anit [1.1K]
1.5 pounds of sugar per dollar.
8 0
3 years ago
Find two consecutive whole numbers that square root 97 lies between
lora16 [44]

Answer: 9 and 10

Step-by-step explanation:

To understand this question we need to first understand how to solve square root equations! The easiest way to learn how to solve square root problems is by finding the reverse of the problem.

For example, if you tried to find the square root of 25, you would reverse the problem to do 5^2 = 5 x 5 = 25.

So if we were to implement this problem, we would look at these two whole numbers.

9^2 = 9 x 9 = 81

10^2 = 10 x 10 = 100

Thus meaning that the only two numbers that the square root of 97 lies between can be 9 and 10!

It's important to rely on your knowledge of multiplication to develop a strong base for square roots.  

8 0
3 years ago
Read 2 more answers
:)
vitfil [10]

Answer:

45-(-15)

430-(-180)

11,560-(-185)

Step-by-step explanation:

just add the two numbers together for diffrence.

6 0
3 years ago
A line has this equation: y = -2x-5 Write an equation for the parallel line that goes through (-3,-5).​
zhuklara [117]

Answer:

Step-by-step explanation:

y + 5 = -2(x + 3)

y + 5 = -2x - 6

y = -2x - 11

3 0
3 years ago
Please help. I’ll mark you as brainliest if correct!
chubhunter [2.5K]

Answer:

\boxed{\sf \ \ \ f^{-1}(x)=1+\sqrt{x} \ \ \ }

Step-by-step explanation:

the minimum of f is for x = 1 and f(1)=0

f is decreasing for x<=1 and increasing for x>=1

so the domain is [1;+\infty[

f^{-1}(f(x))=x =f^{-1}((x-1)^2)\\\\f(f^{-1}(x))=x=(f^{-1}(x)-1)^2

x>=1 so x is positive and we can take the square root

so f^{-1}(x)=1+\sqrt{x}

8 0
3 years ago
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