3.4 can be rewritten as a fraction 19/5 or as a mixed number 3 2/5
1.) The interval of the value of x is from -5 to 1, inclusive. Remember that what is asked is the absolute value, thus the sign does not matter even if you have to subtract x from 5. Thus, the maximum value would be obtained if the x is smaller, which is 1. The minimum value is obtained when x=-5.
Absolute maximum value:
x = - 5f(-5) = ║5 - 7(-5)^2║ = ║-170║=
170Absolute minimum value:
x = 1f(1) = ║5 - 7(1)^2║ = ║-2║=
2
2.) The Mean Value Theorem (MVT) applies to functions that are continuous and differentiable on the closed and open interval of a to b, respectively. Since the function is a quadratic function, MVT can be applied. Then, this means that there is a value of c which is between a and b. This could be determined using this formula according to MVT:
The differentiated form would be f'(x) = -2x. Then,
Thus, x = -1, x = -1/2, and x=0 all lie in the function 4-x^2.
Answer:
he would have had to run 20 more feet then Juan
Step-by-step explanation:
Answer: a) y=-29x-20 b) y=3/5x-18
Step-by-step explanation:
a) m = (-49-38)/(1 - (-2)) = -87/3 = -29
y=-29x+b --> Substitute (1,-49) as a point
(-49)=-29(1)+b
-49=-29+b
-b=-29+49
b=-20
Therefore, the equation of the line is y=-29x-20
b) m = (-18-(-9)/(0-15)) = -9/-15 = 3/5
The y-intercept is (0,-18) as it's where the line intersects the y-axis and x equals 0
Therefore, the equation of the line is y=3/5x-18