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3 years ago

Based on the given information, which conjecture is invalid?

1 answer:

3 0

Valid based on the given information. If not, write invalid. ... So, the statement is invalid. Determine .....disprove a conjecture reached using inductive or deductive .

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NEED HELP ON THIS QUESTION PLEASE

Ilia_Sergeevich [38]

Answer:

Sample space= 1, 2, 3, 4, 5, 6

Outcomes= 2, 4, 6

Probability= Number of outcomes/ total number of outcomes

= 3/6 times 2( as 2 dices are rolled)

=6/12

=1/2

Therefore, the probability of getting 2 even number is 1/2

6 0

3 years ago

Find two nontrivial functions f(x) and g(x) so that f(g(x)) = (-6-3x)^6

creativ13 [48]

Answer:

g(x) = -6 - 3x

f(x) = X^6

Step-by-step explanation:

4 0

4 years ago

“An architect is planning to incorporate several stone spheres of different sizes into the landscaping of a public park, and wor

Artist 52 [7]

Answer:

Part 1) The value that is closest to the cost of finishing a sphere with a 5.50-meter circumference is $900

Part 2) The value that is closest to the cost of finishing a sphere with a 7.85-meter circumference is $1,800

Step-by-step explanation:

Step 1

Find the radius of each sphere

we know that

The circumference of a circle is equal to

$C=2\pi r$

Find the radius of the sphere with a 5.50-meter circumference

For $C=5.50\ m$

assume

$\pi =3.14$

substitute and solve for r

$5.50=2(3.14)r$

$r=5.50/[2(3.14)]=0.88\ m$

Find the radius of the sphere with a 7.85-meter circumference

For $C=7.85\ m$

assume

$\pi =3.14$

substitute and solve for r

$7.85=2(3.14)r$

$r=7.85/[2(3.14)]=1.25\ m$

step 2

Find the surface area of each sphere

The surface area of sphere is equal to

$SA=4\pi r^{2}$

Find the surface area of sphere with a 5.50-meter circumference

For $r=0.88\ m$

assume

$\pi =3.14$

substitute

$SA=4(3.14)(0.88)^{2}$

$SA=9.73\ m^{2}$

Find the surface area of sphere with a 7.85-meter circumference

For $r=1.25\ m$

assume

$\pi =3.14$

substitute

$SA=4(3.14)(1.25)^{2}$

$SA=19.63\ m^{2}$

step 3

Find the cost of finishing each sphere

we know that

To find out the cost , multiply the surface area by $92 per square meter

Find the cost of sphere with a 5.50-meter circumference

$9.73*(92)=\$895.16$

therefore

The value that is closest to the cost of finishing a sphere with a 5.50-meter circumference is $900

Find the cost of sphere with a 7.85-meter circumference

$19.63*(92)=\$1,805.96$

therefore

The value that is closest to the cost of finishing a sphere with a 7.85-meter circumference is $1,800

6 0

3 years ago

Riley called for pizza delivery. She was told the cost is $5 per pizza plus a $6 delivery charge. Fill in the blanks to create a

Nimfa-mama [501]

Answer:

subtract the delivery fee from the 20 dollars. $20 - $6 = $14. 2. Find the number of pizzas with the $14 that she can use. $14 ÷ $5 = 2 R $4.

Step-by-step explanation:

6 0

2 years ago

Select ALL the numbers that are greater than 2.

ivanzaharov [21]

Answer: B and D

8/9 • 2 = 1.77

13/11 • 2 = 2.36

3.7 • 0.5 = 1.85

hope this helped :)

6 0

3 years ago