Solution:
4.2 x 10^6 bp/10^3 bp/seconds = 4.2 + 103 s which is 4200 seconds and equivalents to 70 minutes
In addition, assuming a pause of 2 seconds for re initiating after completing every okazaki fragment and assuming the okazaki fragments average 1000 nucleotide long.
4.2 x 10^6 bp/10^3 bp = 4200 okazaki fragments 4200 * 2 seconds = 8400 seconds which is 140 minutes or 2 hours 20 minutes of pauses alone.
Therefore, overall time would be pauses plus the 70 minutes so total time of 210 minutes. Assuming that the replisome completely disassociates from the DNA after every okazaki fragment and must spend one-minute rebinding.
4200 okazaki fragments. 60 seconds rebinding time per fragment: 4200 x 1 minute = 4200 minutes rebinding time plus 70 minutes for actual replication. 4200 minutes is 70 hours which is almost 3 days.
Answer:
The correct answer would be nucleotide.
Explanation:
Answer:
C
Explanation:
I believe this is the answer.... UWU
Answer:
The two main things happen during Prophase of Mitosis are given below.
1) In prophase stage of mitosis, condensation of chromosomes occurs which is necessary for the formation of daughter cells.
2) Breakdown of nuclei occurs and moves to the opposite poles.
If this phase is not take place during mitosis, the cell will not divide into daughter cells
<span>C.
has strong legs for running
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