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Papessa [141]
3 years ago
5

Graph the following inequality and then select the correct graph below. x - y - 2 ≥ 0

Mathematics
2 answers:
-Dominant- [34]3 years ago
7 0

Answer:

the graph in the attached figure

Step-by-step explanation:

we have

x-y-2\geq 0

Isolate the variable y

-y\geq -x+2 -----> Multiply by -1

y\leq x-2

The solution of the inequality is the shaded area below the solid line

The equation of the line is y= x-2

The slope of the line is positive

The y-intercept of the line is the point (0,-2)

The x-intercept of the line is the point (2,0)

Using a graphing tool

the graph in the attached figure

sweet [91]3 years ago
3 0
To be able to graph any equation, simply solve for y.

You should get y ≤ x - 2          
[the sign switched because you needed to divide by -1 in order to solve for y all the way]

Then use -2 as your y-intercept. This is the point that is at (0,y) on a graph. From the origin, just go down 2 points, and mark your point. 

X is the same as 1/1 x. This is your slope. From point -2, <em>rise</em> 1 point, then <em>run</em> 1 point to the right (because it is positive). From that position, mark another point. You now have enough to make a line, which gives you the completed look of the graph for this equation. 

It should look like this: 

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A college is selling tickets for a winter fund-raiser. One day, Krissa sold 14 adult tickets and 8 student tickets for a total o
FromTheMoon [43]

The statement which explains Krissa’s error is "She switched the prices of the tickets" ⇒ A

Step-by-step explanation:

A college is selling tickets for a winter fund-raiser

  • One day, Krissa sold 14 adult tickets and 8 student tickets for a total of $376
  • The next day, she sold 7 adult tickets and 11 student tickets for a total of $272
  • The price of one adult ticket is a
  • The price of one student ticket is s
  • She wrote and solved the following system of equations.  14a + 8s = 376  and 7a + 11s = 272
  • She found that the price of one student ticket is $20 and the price of one adult ticket is $12

We need to find which statement explains Krissa’s error

∵ The system of equations is:

   14a + 8s = 376  ⇒ (1)

    7a + 11s = 272 ⇒ (2)

Multiply equation (2) by -2 to eliminate x

∵ -14a - 22s = -544 ⇒ (3)

Add equations (1) and (3)

∴ -14s = -168

Divide both sides by -14

∴ s = 12

Substitute the value of s in equation (2) to find a

∵ 7a + 11(12) = 272

∴ 7a + 132 = 272

Subtract 132 from both sides

∴ 7a = 140

Divide both sides by 7

∴ a = 20

∵ a represents the price of one adult ticket

∴ The price of one adult ticket is $20

∵ s represents the price of one student ticket

∴ The price of one student ticket is $12

∵ She found that the price of one student ticket is $20 and

   the price of one adult ticket is $12

- She switched the prices of the tickets

∴ Her error is, she switched the prices of the tickets

The statement which explains Krissa’s error is "She switched the prices of the tickets"

Learn more:

You can learn more about the system of equations in brainly.com/question/2115716

#LearnwithBrainly

5 0
3 years ago
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The inflation rate of the U.S. dollar is 3.7 percent. What this means is that every year, prices increase by 3.7 percent. If a q
Dennis_Churaev [7]
Whatever% of anything is just (whatever/100) * anything.

since we know inflation is 3.7%, what is 3.7% of 1.69?

well is just (3.7/100) * 1.69.

that's how much the quart of oil costs more now.  So simply add that to 1.69.
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2 years ago
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BRAINLIEST ON THE LINE INFO IN PHOTO BELOW
victus00 [196]

Answer:

32 days is my final answer

Step-by-step explanation:

6 0
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There are five people sitting around the dinner table .each person has 2/10of a pie on their plate .how much pie is left ?explai
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No pie is left because 2/10 multiplied by 5 is 10/10, or 1 whole pie, so none of the pie is left.


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4 0
2 years ago
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Cubed root x cubed root x2​
Yuki888 [10]

Answer:

Final answer is \sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x.

Step-by-step explanation:

Given problem is \sqrt[3]{x}\cdot\sqrt[3]{x^2}.

Now we need to simplify this problem.

\sqrt[3]{x}\cdot\sqrt[3]{x^2}

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}

Apply formula

\sqrt[n]{x^p}\cdot\sqrt[n]{x^q}=\sqrt[n]{x^{p+q}}

so we get:

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=\sqrt[3]{x^{1+2}}

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=\sqrt[3]{x^{3}}

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x

Hence final answer is \sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x.

7 0
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