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3 years ago

Where is the axis on a quadrant

Mathematics

1 answer:

dezoksy [38]3 years ago

8 0

Answer:

x axis and y axis divide the coordinate plane into four quadrants.

Step-by-step explanation:

If one coordinate is zero, then the point is located on the x-axis or the y-axis. If y coordinate is zero, then the point is located on the y-axis. If both coordinates are zero, then the point represents the origin.

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If s(x) = x – 7 and t(x) = 4x2 – x + 3, which expression is equivalent to

Vlada [557]

The answer is If you would like to find the expression that is equivalent to (t*s)(x), you can calculate this using the following steps:

s(x) = x - 7
t(x) = 4x^2 - x + 3

(t*s)(x) = t(s(x)) = t(x - 7) = 4(x - 7)^2 - (x - 7) + 3 = 4(x - 7)^2 - x + 7 + 3

The correct result would be 4(x – 7)2 – (x – 7) + 3.

6 0

3 years ago

What is the slant height of a square pyramid that has a surface area of 189 square feet and a side length of 7 feet?

mafiozo [28]

10..............................

5 0

3 years ago

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The vertices of a polygon are P(0,4), Q(5,4), R(5,−3) and S(0,−3). What is

andrezito [222]

Answer:

Perimeter of the polygon p = 24

Step-by-step explanation:

Step(i):-

Given the vertices of a polygon are

P(0,4) ,Q( 5,4) ,R( 5,-3) and S(0,-3)

The distance of PQ

$a = PQ = \sqrt{(4-4)^{2} +(5-0)^{2} } = \sqrt{25} =5$

The distance of QR

$b = Q R= \sqrt{(-3-4)^{2} +(5-5)^{2} } = \sqrt{49} =7$

The distance of RS

$c = RS = \sqrt{(0-5)^{2} +(-3+3)^{2} } = \sqrt{25} =5$

The distance of PS

$d = PS = \sqrt{(0-0)^{2} +(-3-4)^{2} } = \sqrt{49} =7$

Step(ii):-

Perimeter of the polygon

= sum of all sides of polygon

p = a+ b+ c+ d

p = 5+7+5+7

p = 24

Final answer:-

Perimeter of the polygon p = 24

5 0

3 years ago

Slope-intercept form of the equation for the line?

vaieri [72.5K]

Answer:

$\large\boxed{y=-\dfrac{3}{10}x+\dfrac{1}{2}}$

Step-by-step explanation:

The slope-intercept form of an equation of a line:

$y=mx+b$

m - slope

b - y-intercept

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

We have the points from the graph (-5, 2) and (5, -1).

Substitute:

$m=\dfrac{-1-2}{5-(-5)}=\dfrac{-3}{10}=-\dfrac{3}{10}$

We have the equation in form:

$y=-\dfrac{3}{10}x+b$

Put the coordinates of the point (5, -1) to the equation:

$-1=-\dfrac{3}{10}(5)+b$

$-1=-\dfrac{3}{2}+b$

$-\dfrac{2}{2}=-\dfrac{3}{2}+b$ add 3/2 to both sides

$\dfrac{1}{2}=b\to b=\dfrac{1}{2}$

4 0

3 years ago

Please help will highly appreciate it

labwork [276]

Answer:

so I think your trying to find what c is right

if that so.that will be 90° that is an right angle all right angles are 90° I might be wrong because I'm not sure on what your trying to find but I hope I helped just a Little bit

<h2> sorry </h2>

8 0

3 years ago

Read 2 more answers