Answer:
Orion's belt width is 184 light years
Step-by-step explanation:
So we want to find the distance between Alnitak and Mintaka, which is the Orions belts
Let the distance between the Alnitak and Mintaka be x,
Then applying cosine
c²=a²+b²—2•a•b•Cosθ
The triangle is formed by the 736 light-years and 915 light years
Artemis from Alnitak is
a = 736lightyear
Artemis from Mintaka is
b = 915 light year
The angle between Alnitak and Mintaka is θ=3°
Then,
Applying the cosine rule
c²=a²+b²—2•a•b•Cosθ
c² =736² + 915² - 2×, 736×915×Cos3
c² = 541,696 + 837,225 - 1,345,034.1477702404
c² = 33,886.85222975954
c = √33,886.85222975954
c = 184.0838184897 light years
c = 184.08 light years
So, to the nearest light year, Orion's belt width is 184 light years
Answer:
Length of the volleyball court in drawing = 2 mm
Step-by-step explanation:
8 meter = 8 *1000 = 8000 mm
Scale factor = 1 : 8000
Length of the volleyball court in drawing = x
1 : 8000 :: x : 16000

x = 2 mm
Answer:
x>
.
x>\frac{53}{6}
Step-by-step explanation:
12x>140−34
2 Simplify 140-34140−34 to 106106.
12x>106
12x>106
3 Divide both sides by 1212.
x>\frac{106}{12}
Answer:
m<1 = 26°
m<2 = 154°
m<3 = 26°
m<4 = 26°
m<5 = 154°
m<6 = 154°
m<7 = 26°
Step-by-step explanation:
What is required was not stated, however, let's find the value of every angle labelled in this diagram.
✔️m<1 = 180° - 154° (linear pair theorem)
m<1 = 26°
✔️m<2 = 154° (vertical angles theorem)
m<2 = 154°
✔️m<3 = m<1 (vertical angles theorem)
m<3 = 26° (substitution)
✔️m<4 = m<3 (alternate interior angles theorem)
m<4 = 26° (substitution)
✔️m<5 = m<2 (alternate interior angles theorem)
m<5 = 154° (substitution)
✔️m<6 = m<5 (vertical angles theorem)
m<6 = 154° (substitution)
✔️m<7 = m<4 (vertical angles theorem)
m<7 = 26° (substitution)
Answer:

Step-by-step explanation:
