Answer:
Step-by-step explanation:
The slope of the tangent to a curve is the derivative of the curve. We need to find the derivative of the function and then evaluate the derivative at that given x value. The derivative is found using the product rule:

Let's call 3x our f(x) and sin(x) our g(x). Filling in the formula for the derivative using the product rule looks like this:

That gives us the derivative, which is the slope formula that can be used at ANY x value anywhere on the curve to find the slope of the line tangent to the curve at that x value. If we want to find the slope of the tangent line to the curve at x = pi/2, we evaluate the slope formula at x = pi/2 (remember that y' is the same exact thing as the slope):

From the unit circle (or experience, since you're in advaced math), we know that the cosine of pi/2 is 0 and that the sin of pi/2 = 1:
simplifies to
y' (slope) = 3
That means that the slope of the line tangent to the curve at the point x = pi/2 is 3.
The points which satisfy the inequalities in discuss are; Choices D (7,10) and F(8,17).
<h3>Which points omg the answer choices satisfy the system of inequalities?</h3>
It follows from the inequality; x > 5.
Also, substituting 5 for x in; y < 2(x); we have;
y < 10.
Hence, the points which satisfy the inequalities are; (8,17) and (7,10).
Read more on inequalities;
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To find the unit rate, you would have to divide $10.75 by 3, which equals $3.58. The unit rate would be $3.58 per pound.
Answer:
The square root of x will be evaluated first before the addition of 5. Hence (-3)^2 = 9 and 9 +5 = 14, as per your teacher's answer, which is correct. The answer would not be -4.
Answer:

And if we replace we got:

So we expect about 0.8 defective computes in a batch of 4 selected.
Step-by-step explanation:
Previous concepts
The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.
Solution to the problem
For this case we have the following distribution given:
X 0 1 2 3 4
P(X) 0.4096 0.4096 0.1536 0.0256 0.0016
And we satisfy that
and
so we have a probability distribution. And we can find the expected value with the following formula:

And if we replace we got:

So we expect about 0.8 defective computes in a batch of 4 selected.