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3 years ago

This is a picture of a cube and the net for the cube. What is the surface area of the cube?

Mathematics

1 answer:

mina [271]3 years ago

4 0

Answer:

$486\ in^2$

Step-by-step explanation:

we know that

The surface area of the cube is equal to the area of its six square faces

$SA=6b^2$

where

b is the length side of the cube

we have

$b=9\ in$

substitute

$SA=6(9)^2=486\ in^2$

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Work out the surface area of this solid prism

IRISSAK [1]

Answer:

5220

Step-by-step explanation:

1- 20x36/2 is 360

(360 x 2 is 720)

2. 25x50 is 1250

3. 29x50 is 1450

4. 36x50 is 1800

720+1250+1450+1800 is 5220

3 0

2 years ago

3x + 5 and x=2, im having trouble understanding how im suppose to do this

velikii [3]

3x + 5 (first plug in 2 for x )

3(2) + 5 =
6 + 5 = 11

Hope this helps . Give brainliest

6 0

3 years ago

100 times what equil 420

kotegsom [21]

100 x 4.2 would equal 420.
The answer is 4.2

4 0

3 years ago

Read 2 more answers

Which is equivalent to (3 + 2i)(3 + 2i)

Olegator [25]

(3+2i) squared I think

4 0

3 years ago

On any given day, mail gets delivered by either Alice or Bob. If Alice delivers it, which happens with probability 1/4 , she doe

Troyanec [42]

Answer:

(a) The value of fₓ (9.5) is 0.125.

(b) The value of fₓ (10.5) is 0.50.

Step-by-step explanation:

Let X denote delivery time of the mail delivered by Alice and Y denote delivery time of the mail delivered by Bob.

It i provided that:

$X\sim U(9, 11)\\Y\sim U(10, 12)$

The probability that Alice delivers the mail is, p = 1/4.

The probability that Bob delivers the mail is, q = 3/4.

The probability density function of a Uniform distribution with parameters [a, b] is:

$f(x)=\left \{ {{\frac{1}{b-a};\ a, b>0} \atop {0;\ otherwise}} \right.$

The probability density function of the delivery time of Alice is:

$f(X_{A})=\left \{ {{\frac{1}{b-a}=\frac{1}{2};\ [a, b]=[9, 11]} \atop {0;\ otherwise}} \right.$

The probability density function of the delivery time of Bob is:

$f(X_{B})=\left \{ {{\frac{1}{b-a}=\frac{1}{2};\ [a, b]=[10, 12]} \atop {0;\ otherwise}} \right.$

(a)

Compute the value of fₓ (9.5) as follows:

For delivery time 9.5, only Alice can do the delivery because Bob delivers the mail in the time interval 10 to 12.

The value of fₓ (9.5) is:

$f_{X}(9.5)=p.f(X_{A})+q.f(X_B})\\=(\frac{1}{4}\times \frac{1}{2})+(\frac{3}{4}\times0)\\=\frac{1}{8}\\=0.125$

Thus, the value of fₓ (9.5) is 0.125.

(b)

Compute the value of fₓ (10.5) as follows:

For delivery time 10.5, both Alice and Bob can do the delivery because Alice's delivery time is in the interval 9 to 11 and that of Bob's is in the time interval 10 to 12.

The value of fₓ (10.5) is:

$f_{X}(10.5)=p.f(X_{A})+q.f(X_B})\\=(\frac{1}{4}\times \frac{1}{2})+(\frac{3}{4}\times\frac{1}{2})\\=\frac{1}{8}+\frac{3}{8}\\=0.50$

Thus, the value of fₓ (10.5) is 0.50.

5 0

3 years ago